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never [62]
3 years ago
9

2 is a solution for True or False

Mathematics
2 answers:
Tresset [83]3 years ago
4 0

Answer:

False

Step-by-step explanation:

When there is an open circle, it means that it can't be that exact number. If there is a closed circle, it can be that number. This is an open circle, and means that it is less than 2.

Vsevolod [243]3 years ago
3 0

Answer:

False

Step-by-step explanation:

The open circle means you should not include the number it is on.

The inequality would look like, x<2 and not equal to. Therefore, 2 is not a solution.

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(−5)3x7(yz)4 / (3)2x2y8z2
g100num [7]

Answer:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

Step-by-step explanation:

Given:

The expression to simplify is given as:

\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}

In order to simplify this, we have to use the law of indices.

1. (ab)^m=a^mb^m

So, (yz)^4=y^4z^4

Substitute this value in the above expression. This gives,

=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)

Now, we use another law of indices.

2. \frac{a^m}{a^n}=a^{m-n}

So,  \frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2

Substitute these values in the above expression. This gives,

=\frac{-15}{6}\times x^5\times y^{-4}\times z^2\\\\=\frac{-5x^5y^{-4}z^2}{2}

Finally, we further simplify it using the law a^{-m}=\frac{1}{a^m}

So, y^{-4}=\frac{1}{y^4}

Therefore, the given expression is simplified as:

\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}

5 0
3 years ago
I need help can you help
saveliy_v [14]

Answer:

the awnser is 30

Step-by-step explanation:

mario and peach equal the same, so you would have to do 36÷3 and that equals 12, so then you look at mario divided by toad, and you would do 12÷2 to get 6, so toad would be 6, and that make bowser 0. so it would be 12+0+12+6=30

8 0
3 years ago
Chad ran a red light and hit another car. He decided to file a claim for damage
pochemuha

Answer:

Comprehensive deductible

Step-by-step explanation:

There is nothing called Premium deductible rather deductible determines how higher of lower a premium on a subject matter of insurance can be. Deductible is the amount with the insured have to bear at loss and any excess above the loss will be compensated by the insurance company.

Comprehensive deductible is the application to only to comprehensive insurance which was what Chad had on his motor vehicle. Comprehensive insurance covers majority of peril that happens to the insured vehicle. Therefore, comprehensive deductible is the deductible Chad has to bear himself before the insurance company take other losses upon theirself..

If he had $500 deductible on his car and total repair cost $700, then he will bear the $500 while the insurance company is entitled to pay only $200 as per policy statement.

6 0
3 years ago
Read 2 more answers
Suppose that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each
stich3 [128]

We have been given that  you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each bounce. We are asked to find the total distance traveled by up and down from the time it was dropped from the window until the 25th bounce.            

We will use sum of geometric sequence formula to solve our given problem.

S_n=\frac{a\cdot(1-r^n)}{1-r}, where,

a = First term of sequence,

r = Common ratio,

n = Number of terms.

For our given problem a=50, r=50\%=\frac{50}{100}=0.5 and n=25.

S_{25}=\frac{50\cdot(1-(0.5)^{25})}{1-0.5}

S_{25}=\frac{50\cdot(1-0.0000000298023224)}{0.5}

S_{25}=\frac{50\cdot(0.9999999701976776)}{0.5}

S_{25}=100\cdot(0.9999999701976776)

S_{25}=99.99999701976776\approx 100

Therefore, the ball will travel 100 meters and option B is the correct choice.

 

4 0
3 years ago
Write 894,217 in expended form an using number names
storchak [24]
Eight hundred ninety four thousand, two hundred and seventeen. I hope this helps.
5 0
3 years ago
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