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Nezavi [6.7K]
2 years ago
11

Please answer this correctly

Mathematics
2 answers:
gtnhenbr [62]2 years ago
8 0

Answer:

The dimensions are 4 millimetres by 10 millimetres

Step-by-step explanation:

The area of the first rectangle is 5*8=40 square millimetres. Let's call the width of they yellow rectangle w, and the length l. Now you can set up the following system of equations:

l*w=40

2l+2w=28

Isolate one of the variables to substitute:

l=40/w

2(40/w)+2w=28

80/w+2w=28

Multiply both sides by w:

80+2w^2=28w

Move everything to one side:

2w^2-28w+80=0

Factor the quadratic:

2(w^2-14w+40)=0

2(w-10)(w-4)=0

w=4 or 10

l= 10 or 4

Hope this helps!

Reil [10]2 years ago
3 0

Answer:

4 and 10

Step-by-step explanation:

l*w=40

2l+2w=28

l=40/w

2(40/w)+2w=28

80/w+2w=28

80+2w^2=28w

2w^2-28w+80=0

2(w^2-14w+40)=0

2(w-10)(w-4)=0

w=4 or 10

l= 10 or 4

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define systems</u>

13x - 6y = 22

x = y + 6

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                              13(y + 6) - 6y = 22
  2. Distribute 13:                                 13y + 78 - 6y = 22
  3. Combine like terms:                      7y + 78 = 22
  4. Isolate <em>y</em> term:                                7y = -56
  5. Isolate <em>y</em>:                                         y = -8

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                    x = y + 6
  2. Substitute in <em>y</em>:                                     x = -8 + 6
  3. Add:                                                      x = -2
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3 years ago
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