440 cubits to feet would be 660ft. Have a good day!
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
1/2
Step-by-step explanation:
1/2
<u>40 is shown 3 times, 41 is shown 3 times, 42 is shown 3 times, and 43 is shown 3 times. </u>
I would put as the answer that <u>all the numbers are equally shown the same amount of times. </u>
