Answer:
a. 80.83 ft b. 40.42 ft
Step-by-step explanation:
Let h = height of pole = 70 ft, L = length of cable and x = distance of cable on ground to pole and Ф = angle between cable and ground.
a) How long is the cable?
Since L, h and x form a right-angled triangle with angle Ф and h being the opposite side to Ф and L being the hypotenuse side, by trigonometric ratios,
sinФ = h/L
L = h/sinФ
L = 70 ft/sin60°
L = 70 ft/0.8660
L = 80.83 ft
b) How far from the pole should the cable be attached to the ground?
Since L, h and x form a right-angled triangle with angle Ф and h being the opposite side to Ф and x being the adjacent side, by trigonometric ratios,
tanФ = h/x
x = h/tanФ
x = 70 ft/tan60°
x = 70 ft/1.7321
x = 40.42 ft
Answer:
y = 3x - 5
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x - 12 ← is in slope- intercept form
with slope m = 3
Parallel lines have equal slopes , then
y = 3x + c ← is the partial equation
to find c substitute (1, - 2 ) into the partial equation
- 2 = 3 + c ⇒ c = - 2 - 3 = - 5
y = 3x - 5 ← equation of parallel line
Answer:
Step-by-step explanation:
1. Find the least common multiple of the denominators
The least common multiple of 3 and 3 is 3.
2. Factor out ⅓.
Answer:
21.5 km
Step-by-step explanation:
We have to find the distance between two boat
We are given that
AC=2.1 km
BC=3.5 km
We have to find BC
The angle between two boat =110 degrees
Using cosine law
BC=
BC=
BC=
BC=21.507 km
Hence, the distance between two boat is 21.5 km
You can change mm into cm. Since 1 cm is equal to 100 mm, divide 500 by 100 to get 5 cm. Add 30 and 5 to get 35. The two line segments are 35 cm together.
