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marin [14]
4 years ago
10

Help Solve Domain and Range

Mathematics
2 answers:
Zielflug [23.3K]4 years ago
6 0

You would likely benefit far more from learning the definitions of "domain" and "range" than from being given the domain and range in each of these cases.

The domain of a function includes all values of the independent variable for which the function is defined (that is, for which there is a graph). In Case 1, x can have any real value, and so the domain is (-infinity, infinity).

The range of a function includes all values that the dependent value can have (that is, for which there is a graph). In Case 1, y can take on any real value, and so the range is (-infinity, infinity).


Contrast this case to Case 2. Here, y has only ONE value, so the range is simply y=2, or {2}. x can take on any value, so the domain is (-infinity, infinity).

vova2212 [387]4 years ago
3 0

Domain and Range are simply the areas where a graph exist.

Domain is in what values of X a Y value exists for, and Range is what vales of Y existences

For example, lets look at number 1:

looking at the graph, we can see that the Y values will all be taken, so the Range is -∞<y<∞

We can also see that all the x values will also be used, so -∞<x<∞


Lets look at 6

As we can see only some of the values are used, and only some x values are legal.

The domain is -1<x<8

and the range is 1<y<7


Lets look at question 2:

as we can see, every x value is used, so the domain is -∞<x<∞

but the range is locked at 2, so the range is simply y=2

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To solve this system by addition, notice that if we add these two equations together, neither one of our variables will cancel out.

In this situation, we need to set things up so that when we do add our two equations together, one of the variables will cancel out.

Notice that we have a 10x in our second equation. if we had a -10x in our first equation, then the x's would cancel out.

To create a -10x, we can multiply the top equation by -2 to get a -10x.

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Now the x's cancel. Just add the equations together

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Now plug y into either one of the equations

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Step-by-step explanation:

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==> <u>(</u><u>680</u><u>)</u><u>/</u><u>1</u> ×(<u> 5</u><u>)</u><u>/</u><u>1</u><u>0</u><u>0</u>

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