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alina1380 [7]
3 years ago
13

Which data set is represented by the modified box plot? Box and whisker plot on a number line from 90 to 180 in increments of 5.

The whisker ranges from 124 to 152. The box ranges from 130 to 149 with the vertical bar inside the box at 138. One dot mark above one hundred and one. One dot mark above one hundred and seventy-eight.
128, 146, 152, 128, 178, 101, 124, 144, 130, 126, 149

138, 146, 152, 138, 178, 110, 124, 144, 130, 136, 149

138, 146, 152, 138, 178, 101, 124, 144, 130, 136, 149

138, 146, 152, 138, 169, 101, 124, 144, 130, 136, 149
Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0
C. Just took the test.
pentagon [3]3 years ago
7 0

Answer:

Option: 3 is the correct answer:

138, 146, 152, 138, 178, 101, 124, 144, 130, 136, 149

Step-by-step explanation:

We will arrange each of the given options in the increasing order of the data points:

1)    101     124   126   128    128   130    144   146    149    152    178

2)    110   124   130   136   138   138   144    146    149   152    178

3)    101  124   130   136   138 <u>  </u><u>138</u>  144    146   149   152   178

4)    101   124   130   136   138   138   144    146    149   152    169

Now according to the question we have:

Minimum value=124

Lower quartile i.e. Q_1=130

Median or middle quartile i.e Q_2=138

Upper quartile i.e. Q_3=149

Maximum value=152

Also, it is given that :

  • One dot mark above one hundred and one.
  • One dot mark above one hundred and seventy-eight.

Hence, the data set that satisfy these conditions are:

138, 146, 152, 138, 178, 101, 124, 144, 130, 136, 149

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cost of one cinnamon sugar cookies = $ 0.3

<h3><u>Solution:</u></h3>

Let "p" be the cost of one peppermint cookies

Let "c" be the cost of one cinnamon sugar cookies

<u><em>To find: cost of each cookie</em></u>

<h3><u><em>On  the first day, they sold 120  peppermint cookies and 30  cinnamon sugar cookies for a  total of $81</em></u></h3>

We can frame a equation as:

120  peppermint cookies x cost of one peppermint cookies + 30  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 81

120 \times p + 30 \times c = 81

120p + 30c = 81  --------- eqn 1

<h3><u><em>The next day  they made $60 by selling 70  peppermint cookies and 60  cinnamon sugar cookies</em></u></h3>

70  peppermint cookies x cost of one peppermint cookies + 60  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 60

70 \times p + 60 \times c = 60

70p + 60c = 60 --------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "p" and "c"

Multiply eqn 1 by 2

240p + 60c = 162  --- eqn 3

Subtract eqn 2 from eqn 3

240p + 60c = 162

70p + 60c = 60

(-) -------------------------

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<h3>p = 0.6</h3>

Substitute p = 0.6 in eqn 1

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120(0.6) + 30c = 81

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30c = 9

<h3>c = 0.3</h3>

<u><em>Summarizing the results:</em></u>

<em>cost of one peppermint cookies = $ 0.6</em>

<em>cost of one cinnamon sugar cookies = $ 0.3</em>

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