Answer:
i believe its B= (1,5)
Step-by-step explanation:
Answer:
90 hardcover books
Step-by-step explanation:
We can solve this by setting up a couple of equations.
Let's allow x to represent the number of paperbacks Tim owns, and allow y to represent the number of hardcover books he owns.
Using the information in the question, we can write the equations:
1)x = 4y-3
2) x+y=447
Let's rearrange equation 1 so that it is in standard form:
x-4y=-3
And then let's multiply equation 2 by 4 so that we can cancel out y when we solve the system of equations:
4(x+y=447)
4x+4y=1,788
Then we can add the two equations and solve for x:
1) x-4y=-3
+ 2)4x+4y=1,788
------------------------------------
5x=1,785
x=357
So now we now the number of paperback books Tim has is 357. Let's plug this into one of the original equations to solve for the number of hardcover books (y):
357+y=447
y=90
And now we know that Tim owns 90 hardcover books.
9514 1404 393
Answer:
142
Step-by-step explanation:
The first term of this arithmetic sequence is -10. The common difference is -8-(-10) = 2. The n-th term is ...
an = a1 +d(n -1)
an = -10 +2(n -1) = 2n -12
Then the 77th term is ...
a77 = 2(77) -12 = 154 -12
a77 = 142
The 77th term is 142.
Answer:
3.14 * r^2 * h
Step-by-step explanation:
Answer:
standard divisor: 525.00
Step-by-step explanation:
The standard divisor is found by dividing the total number of residents to be represented, by the number of representatives. Here, that is 7875 divided by 15. The resulting standard divisor is 525 (exactly).
By Hamilton's method, the number of residents in each district is divided by this number, and the integer and fraction of the quotient are recorded.
If the total of integers is less than the total number of representatives, then the difference is apportioned to the districts according to the values of the fractions.
Here, the total of quotient integers is 13, so 2 additional representatives need to be apportioned. The two largest fractions are 0.77 associated with District 5, and 0.58 associated with District 1. These two districts, then, get the "extra" representatives. (1 is added to the "integer" for those districts.)
Final assignments of representatives to districts are seen in the rightmost column of the spreadsheet.
