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3 years ago

What is true about angles 2 and 7 In the picture below?

Mathematics

1 answer:

Troyanec [42]3 years ago

5 0

Answer:

They are on the exterior sides of the parallel lines and are on alternating sides of the transversal.

Step-by-step explanation:

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-x-6=3<br> How do u do this

Hatshy [7]

Answer:

x= -9......................

3 0

3 years ago

Read 2 more answers

What is the quotient of 3.12 x 108 and 2.6 x 105 expressed in scientific notation?

Gnoma [55]

Answer:

1.2 * 10^3

Step-by-step explanation:

3.12 * 10^8

=========

2.6 * 10^5

Start by doing 3.12 / 1.6 = 1.2 and that is the correct number of sig digs.

Now get the power on the 10. When dividing, the powers subtract.

10^(8 - 5)

10^ 3

The answer is 1.2 * 10^3

7 0

3 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$

(because the point $(x,y)=(6,1)$ corresponds to $(u,v)=(1,2)$ )

$\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}$

4 0

3 years ago

Solve for y<br> 8x + y = 32

oksian1 [2.3K]

Answer:

Subtract 8x8x from both sides of the equation.

y=32−8x

8 0

3 years ago

a square has the side measurment of s = 2 3 over 2 using the formula 1= s^2 find the area of the square

vitfil [10]

Check the picture below.

$\bf A=s^2\qquad s=2\frac{3}{2}\qquad A=\left( 2\frac{3}{2} \right)^2\implies A=\left( \frac{2\cdot 2+3}{2} \right)^2
\\\\\\
A=\left( \frac{7}{2} \right)^2\implies A=\cfrac{7^2}{2^2}\implies A=\cfrac{49}{4}\implies A=12\frac{1}{4}$

3 0

3 years ago