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matrenka [14]
3 years ago
9

Julia rides her horse 18 km with a constant speed of 6 km/hr and another 24 km with a constant speed of 12 km/hr. What is her av

erage speed for the total trip?
14 points!
Mathematics
1 answer:
tester [92]3 years ago
4 0

The answer is 8.4km/hr


(6+6+6+12+12)÷5=8.4


I don't know how to explain it it's as easy as 2+2 but as hard as explaining how to get 4 from 2+2

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Find the area of a circle with the circumference 32pi
Stella [2.4K]

Answer:

A=πr2

C=2πr

Solving forA

A=C2

4π=322

4·π≈81.48733

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3 years ago
Dana needs 300 pickets for her colorful picket fence. She wants equal amounts of each of her 4 selected colors. She already has
Pavlova-9 [17]

Dana would need 75 pickets of each color to have an equal amount.

75x4=300

She would need 43 more red pickets to equal 75. (32+43=75)

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3 years ago
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Evaluate the expression under the given conditions. tan(2); cos() = 5 13 , in quadrant i
Nataliya [291]

The solution to given expression tan(2θ) is 22.615°

For given question,

We have been given an expression tan(2θ)

Given that cos(θ) = 5/13, and θ is in quadrant 1.

We know that the trigonometric identity

sin²θ + cos²θ = 1

⇒ cos²θ = (5/13)²

⇒ sin²θ = 1 - 25/169

⇒ sin²θ = 169 - (25/169)

⇒ sin²θ = 144/169

⇒ sin(θ) = 12/13

We know that the identity cos(2x) = cos²x - sin²x

⇒ cos(2θ) = cos²θ - sin²θ

⇒ cos(2θ) = 25/169 - 144/169

⇒ cos(2θ) = -119/169

And sin(2x) = 2sin(x)cos(x)

⇒ sin(2θ) = 2sin(θ)cos(θ)

⇒ sin(2θ) = 2 × 12/13 × 5/13

⇒ sin(2θ) = 120/169

We know that, tan(x) = sin(x)/cos(x)

⇒ tan(2θ) = sin(2θ)/cos(2θ)

⇒ tan(2θ) = (120/169) / (-119/169)

⇒ tan(2θ) = 120 / (-119)

⇒ tan(2θ) = -1.008

Since θ is in quadrant 1, tan(2θ) = 1.008

⇒ 2θ = arctan(1.008)

⇒ 2θ = 45.23

⇒ θ = 22.615°

Therefore, the solution to given expression tan(2θ) is 22.615°

Learn more about the expression here:

brainly.com/question/14961928

#SPJ4

7 0
2 years ago
Can someone answer 5,6,7? can you also tell me how to solve them so i can do better in the future?
Alborosie
Like this , this is the rules of index

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The means and mean absolute deviations of the individual times of members of two relay swim teams are shown in the table below.
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See the attached picture for the solution:

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