3 lines are shown. A line with points T, R, W intersects with a line with points S, R, V at point R. Another line extends from p
oint R to point U in between angle V R W. Which pair of angles are vertical angles? AngleWRU and AngleSRT AngleWRS and AngleVRT AngleVRU and AngleTRS AngleVRT and AngleSRT
2 answers:
Answer:
The vertical angles are ∠ WRS and ∠ VRT ⇒ 2nd answer
Step-by-step explanation:
* <em>Lets explain the meaning of the vertical angles</em>
- Vertical angles are the angles opposite to each other when two lines
are intersected
- The vertical angle are equal in measures
- <em>Look to attached figure which represents the lines </em>
∵ Line TW intersects line SV at R
∴ ∠ WRV and ∠ SRT are vertical angle
∴ <u><em>∠ WRS and ∠ VRT</em></u> are vertical angle
∵ RU is between the rays of angle VRW
∴ RU intersects the lines TW and SV at R
∴ No vertical angles between RU and the other two lines because
it intersects them its endpoint R
* <em>Now lets look to the answer to chose the right one</em>
- ∠ WRU and ∠ SRT are not vertical angles
- <em><u>∠ WRS and ∠ VRT are vertical angles </u></em>
- ∠ VRU and ∠ TRS are not vertical angles
- ∠ VRT and ∠ SRT are not vertical angles
You might be interested in
Answer:
C. 5.2 cm
Step-by-step explanation:
Arc length formula:
where s = arc length
n = central angle of arc
r = radius of circle
diamter = d = 10 cm
r = d/2 = 10 cm/2 = 5 cm
n = 60 deg
Answer: 5.2 cm
Answer:
The value to be added to the polynomial x³ - 6·x² + 11·x + 8 so that it is completely divisible by 1 - 3·x + x² is -(x + 11)
Step-by-step explanation:
By long division, we have;
= x - 3
-(x³ - 3·x² + x)
-3·x² + 10·x + 8
-(-3·x² + 9·x -3)
x + 11
Therefore, -(x + 11) should be added to the polynomial x³ - 6·x² + 11·x + 8 so that it is completely divisible by 1 - 3·x + x².
That is (x³ - 6·x² + 11·x + 8 - x - 11) ÷ (1 - 3·x + x²) = x - 3.