A) > since it is 50c per weekday and 75c each weekend assuming it allows for the 2 days each saturday/sunday.
50c * 5 = $2.50 since there are 5 days in weekdays
75c * 2 = $1.50 since there are 2 days in the weekend
Add $2.50 and $1.50 to get $4.00
b) For 3 school days we know it is a weekday on the school week.
So perform 50c * 3 which gives us <span>$1.50
</span>c) 12 days off from school is 10 weekdays and 1 weekend or 2 days of 75c
So now just do 50c * 10 which is $5.00 and 75c * 2 which is $1.50
Add $5.00 and $1.50 and we get $6.50
d) 4 weeks = 20 weekdays since 5 *4 = 20 and 8 days in each weekend since 2 * 4 = 8
Now that we have the amount of weekdays and weekend days we can multiply.
50c * 20 = $10.00
75c * 4 = $3.00
Add $10.00 and $3.00 to get $13.00 for 4 weeks.
e) We have 1 day of the weekend and 2 weekdays here.
50c * 2 = $1.00
75c * 1 = 75c
<span>$1.00 + 75c = $1.75 in those 3 days listed.
</span>
Add all these together to get your total value.
$4.00 + $1.50 + $6.50 + $13.00 + $1.75 = $26.75
Answer:
Yes, -1 is reasonable.
Step-by-step explanation:
Sum means adding +.
(6*-1) - 5 = -11
The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.
Rest Area=((1+7)/2, (-4+1)/2)
Rest Area=(4, -1.5)
The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.
d^2=(x2-x1)^2+(y2-y1)
d^2=(7-1)^2+(1--4)^2
d^2=36+25
d^2=61
d=√61 and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:
D=5.38√61 mi
D≈42.02mi (to nearest hundredth of a mile)
Answer:
Step-by-step explanation:
Since the length of both legs of the right angle triangle are given, we would determine the hypotenuse, h by applying Pythagoras theorem which is expressed as
Hypotenuse² = one leg² + other leg²
Therefore,
h² = (3a)³ + (4a)³
h² = 27a³ + 64a³
h² = 91a³
Taking square root of both sides,
h = √91a³
The formula for determining the perimeter of a triangle is expressed as
Perimeter = a + b + c
a, b and c are the side length of the triangle. Therefore, the expression for the perimeter of the right angle triangle is
√91a³ + (3a)³ + (4a)³
= √91a³ + 91a³
You would divide the 2/3 by 4 which would be 1.6 recurring and then put that back into a fraction which would be 1/6. I'm not sure if his is correct but this what is learnt ♡♡chyna
