Step 1
Find the volume of <span>a sink
Volume sink=(4/6)*pi*r</span>³ (<span>half-sphere)
Diameter=20 in--------------> r=D/2-----------> r=10 in
</span>Volume sink=(4/6)*pi*10³---------> (2000/3)*pi in³ --------> 2093.33 in³
<span>(a) What is the exact volume of the sink?
the answer part a) is </span>(2000/3)*pi in³ (2093.33 in³)
<span>(b) One conical cup has a diameter of 8 in. and a height of 6 in. How many cups of water must Ki’von scoop out of the sink with this cup to empty it?
</span>volume of a conical cup=pi*r²*h/3
diameter=8 in--------------> r=4 in
h=6 in
volume of a conical cup=pi*4²*6/3-----------> 32*pi in³
if one cup---------------------> 32*pi in³
X---------------------------> (2000/3)*pi in³
X=(2000/3)*pi/(32*pi)------------> 20.83----------> 21 cups
the answer part b) is 21 cups
(c) One cylindrical cup has a diameter of 4 in. and a height of 6 in. How many cups of water must he scoop out of the sink with this cup to empty it?
volume of a cylindrical cup=pi*r²*h
diameter=4 in--------------> r=2 in
h=6 in
volume of a cylindrical cup=pi*2²*6-----------> 24*pi in³
if one cup---------------------> 24*pi in³
X---------------------------> (2000/3)*pi in³
X=(2000/3)*pi/(24*pi)------------> 27.77----------> 28 cups
the answer part c) is 28 cups
Answer:
x=0, x= - 3, x=9
Step-by-step explanation:
f(x)=7/2x(x+3)(x-9)
f(x) doesn't exist for x=0,-3,9
as

vertical asymptote:
x=0, x= - 3, x=9
The matrices are
S =(4 11 T= ( -8 11
-3 -8) 3 4 )
Inverse of a matrix is a matrix derived from another matrix such that if you pre- multiply it with the original matrix you get a unit matrix.
if we multiply S and T
ST will be
( 4 11 × (-8 11 = ( 1 0
-3 -8) -3 -4) 0 1)
and also TS
( -8 11 × (4 11 = ( 1 0
-3 -4) -3 -8) 0 1)
therefore, matrices S and T are inverses of each other because ST = TS= I
.