Question

A square has a side length of 7 centimeters. A circle has a diameter of 7 centimeters. What is true about the areas of the two figures?

Answer 1

Answer:

Area of Square having side length equal to 7cm

    =(7)²

  =49 cm²

because ,Area of square=Side × Side

⇒Area of Circle having diameter 7 cm will be

      $\text{radius}=\frac{\text{Diameter}}{2}\\\\\text{Area of circle}=\pi \times r^2\\\\=\frac{22}{7}\times (\frac{7}{2})^2\\\\=\frac{22\times 49}{7\times 4}\\\\=\frac{77}{2}\\\\=38.5 \text{cm}^2$

  Area of square is larger than Area of circle by

    =49-38.5

   =10.5 cm²

Answer 2

Answer:  The area of the circle will be eleven-fourteenth of the area of square.

Step-by-step explanation:  Given that a square has a side of length 7 cm and a circle has a diameter of 7 cm. We need to find the statement which is true about the areas of these two figures.

The area of the square will be

$S_a=7^2=49~\textup{cm}^2.$

And, the area of the circle will be

$C_a=\pi r^2=\pi \times \left(\dfrac{7}{2}\right)^2=\dfrac{\pi}{4}\times 49=\dfrac{22}{7\times 4}\times 49\\\\\Rightarrow C_a=\dfrac{11}{14}\times S_a.$

Thus, the area of the circle will be eleven-fourteenth of the areq of the square.