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Alekssandra [29.7K]
3 years ago
8

Please help!!! asap ( 15 pts!!)

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

A) 40

B) 96

C) 60

D) 70

:)


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Write an equation that has a slope of -2 and passes through (-6, 2)
Lelechka [254]

Answer:

y = - 2x - 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute (- 6, 2) into the partial equation

2 = 12 + c ⇒ c = 2 - 12 = - 10

y = - 2x - 10 ← equation of line

5 0
3 years ago
Is is square root of 1.6875 a rational number
mamaluj [8]

<em><u>Question:</u></em>

Is square root of 1.6875 a rational number ?

<em><u>Answer:</u></em>

Square root of 1.6875 a rational number is not a rational number

<em><u>Solution:</u></em>

Given that we have to find square root of 1.6875 and determine if it is rational number or not

Let us first find square root of 1.6875

\sqrt{1.6875} = 1.29903810568

Let us understand about rational number

A rational number is a number that can be expressed as a fraction (ratio) in the form \frac{p}{q} where p and q are integers and q is not zero.

When a rational number fraction is divided to form a decimal value,  it becomes a terminating or repeating decimal.

So the number 1.29903810568 is not a rational number

<em><u>In other words we can say,</u></em>

Only the square roots of square numbers are rational. Here 1.6875 is not a perfect square. So it is not rational number

4 0
3 years ago
a student is reading a fictional book at about 300 words per a minute. convert this rate to words per second
Harrizon [31]

300 words divided by 60 seconds would equals 5 words a second

hope this helps

6 0
3 years ago
Which compares the modes of the data?
sveta [45]

Answer:

I think C

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the constant of variation k for the direct variation x -1 0 2 5 f(x) 2 0 -4 -10
Fofino [41]

Answer:

k = -2

Step-by-step explanation:

x     -1   0   2     5

f(x)  2   0  -4  -10

ƒ(x) = kx

Substitute a pair of values for x and ƒ(x)

-10 = k×5

Divide each side by 5

k = -2

The constant of variation k = -2.

8 0
3 years ago
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