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podryga [215]
3 years ago
7

An artist is making a scale model of a statue. On the model 2 inches represents 1 foot on the actual statues. Which graph best r

epresents this relationship?
Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

Step-by-step explanation:

eimsori [14]3 years ago
6 0
An artist is making a scale model of a statue. On the model 2 inches represents 1 foot on the actual statues. Which graph best represents this relationship?
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-3 &lt; 4x -7 &lt; 4<br> NEED HELP ASAP!!
TiliK225 [7]

Answer:

X=3

Step-by-step explanation:

6 0
3 years ago
Solve the following:<br> a) 4x 3= 2x + 7<br><br> b) 2x+6= 7x14
nikdorinn [45]
<h2><u>Correct question</u> : 4x - 3 = 2x + 7 </h2>

<h2><u>Solution</u> : 4x - 3 = 2x + 7 </h2>

4x - 2x = 7 + 3 \\  \\ 2x = 10 \\  \\ x =  \frac{10}{2}  \\  \\ x = 5.

<h2>•••••••••••••••••••••••••••••••••••••••</h2>

<h2><u>Correct Question</u> : 2x + 6 = 7x - 14</h2>

<h2><u>Solution</u> : 2x + 6 = 7x - 14</h2>

2x - 7x =  - 14 - 6 \\  \\  - 5x =  - 20 \\  \\ x =  \frac{20}{5}  \\  \\ x = 4.

7 0
1 year ago
Rewrite 4 1/2=2 <br> please
Luda [366]

The logarithmic expression of 4^(1/2) = 2 is \log_4(2) = \frac 12

<h3>How to rewrite the expression?</h3>

The expression is given as:

4^(1/2) = 2

Take the logarithm of both sides

log(4^(1/2)) = log(2)

Apply the change of base rule

1/2log(4) = log(2)

Divide both sides by log(4)

1/2 = log(2)/log(4)

Change the base

\frac 12 =\log_4(2)

Rewrite as:

\log_4(2) = \frac 12

Hence, the logarithmic expression of 4^(1/2) = 2 is \log_4(2) = \frac 12

Read more about logarithmic expression at:

brainly.com/question/24211708

#SPJ1

8 0
2 years ago
Given the equations written in Slope Intercept form what is the Slope? y=2x+1
luda_lava [24]

Answer:

Step-by-step explanation:

The slope would be rise 2 over 1

7 0
3 years ago
Read 2 more answers
Descried how to derive the quadratic formula from a quadratic equation in standard form
Aleks [24]

Answer:

The standard form of a quadratic equation is:

ax^2+bx+c=0, a\neq 0

Quadratic Formula Derivation:

ax^2+bx+c=0\\

$x^2+\frac{b}{a}x+\frac{c}{a} =0 $

$x^2+\frac{b}{a}x = -\frac{c}{a}$

Completing the Square:

$x^2+\frac{b}{a}x +\frac{b^2}{4a^2} = \frac{b^2}{4a^2}-\frac{c}{a}$

$  ( x+\frac{b}{2a} )^2 =  \frac{b^2-4ac}{4a^2}  $

Square Root property:

$x+\frac{b}{2a}  = \pm \sqrt{ \frac{b^2-4ac}{4a^2}}   $

$x  = -\frac{b}{2a} \pm  { \frac{\sqrt {b^2-4ac}}{2a}}   $

$x  =  \frac{-b\pm\sqrt{b^2-4ac}} {2a}  }   $

8 0
3 years ago
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