All categories

3 years ago

How do you write a word form for 4.293

Mathematics

2 answers:

kherson [118]3 years ago

6 0

Four and two hundred ninety three thounds hope it helps

pychu [463]3 years ago

5 0

Four and two hundred ninety-three thousandths

You might be interested in

What is the first step in solving the equation 2/3x+1/3+2=5?

julsineya [31]

The first step is combining like terms. On the left side of the equation add all the numbers together that don't have and x (1/3 +2)

Hope this helped! Let me know if there is anything else I can do!

7 0

3 years ago

What is 200% of 90? Order from least to greatest? 68% 0.63 13/20

Mandarinka [93]

200% of 90 is 180.

13/20=65/100 so

.63 < 13/20 < 68%

4 0

4 years ago

2. -6 < -3; Divide both sides by -3

elena-s [515]

The answers for one, two, and three are:
False
True
True

8 0

3 years ago

Find the equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

Solution:

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

The slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that product of slopes of given line and slope of line perpendicular to given line is equal to -1

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

Thus the required equation of line is:

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

3 years ago

Find area of a parallelogram with a height of 8 inches and a base of 14 inches

12345 [234]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{112 \: {inches} \: ^{2} }}}}}$

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

Finding the area of a parallelogram

$\boxed{ \sf{area \: of \: parallelogram \: = \: base \: \times \: height}}$

⇒ $\sf{area \: of \: parallelogram \: = \: 14 \: \times 8}$

⇒ $\sf{area \: of \: parallelogram = 112 \: {inches}^{2} }$

Hope I helped!

Best regards! :D

4 0

3 years ago