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natta225 [31]
3 years ago
10

Help me with Geometry

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
P&({{ 3}}\quad ,&{{ 5}})\quad 
%  (c,d)
Q&({{ c}}\quad ,&{{ d}})
\end{array}\quad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(-2,0)\\\\
-----------------------------\\\\
\left(\cfrac{{{ c}} + {{ 3}}}{2}\quad ,\quad \cfrac{{{ d}} + {{ 5}}}{2} \right)=(-2,0)M\implies 
\begin{cases}
\cfrac{c+3}{2}=-2\\\\
\cfrac{d+5}{2}=0
\end{cases}

if you solve those equations for "c" and "d" respectively, you'd get, well the Q point of c,d
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stira [4]

Answer:

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Step-by-step explanation:

The isosceles triangle has two equal sides in length, and its base angles are equal in measures

In ΔJKL

∵ ΔJKL is an isosceles triangle with vertex K

→ That means the equal sides are JK and KL

∴ JK = KL

∵ JK = 8x and KL = 13x - 15

→ Equate them

∴ 13x - 15 = 8x

→ Add 15 to both sides

∵ 13x - 15 + 15 = 8x + 15

∴ 13x = 8x + 15

→ Subtract 8x from both sides

∵ 13x - 8x = 8x - 8x + 15

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→ Divide both sides by 5 to find x

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∵ The base angles are equal in measures

∴ m∠KJL = m∠KLJ

∵ m∠KJL = 5y - 3

∴ m∠KLJ = 5y - 3

∵ The sum of the measures of the angles of a Δ is 180°

∴ m∠KJL + m∠KLJ + m∠JKL = 180°

∵ m∠JKL = 76°

→ Substitute the measures of the 3 angles in the equation

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∵ (5y + 5y) + (76 - 3 - 3) = 180

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→ Subtract 70 from both sides

∵ 10y + 70 - 70 = 180 - 70

∴ 10y = 110

→ Divide both sides by 10 to find y

∴ y = 11

∴ The values of x and y are x = 3 and y = 11

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