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erma4kov [3.2K]
3 years ago
8

Angle BAC is congruent to angle DCA then BAC = DCA by ?

Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

7

Step-by-step explanation:

yah

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What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!
Radda [10]

Two main facts are needed here:

1. The logarithm \log x, regardless of the base of the logarithm, exists for x>0.

2. The square root \sqrt x exists for x\ge0.

(in both cases we're assuming real-valued functions only)

By (2) we know that \sqrt{2x-1} exists if 2x-1\ge0, or x\ge\dfrac12.

By (1), we know that \log(\sqrt{2x-1}+3) exists if \sqrt{2x-1}+3>0, or \sqrt{2x-1}>-3. But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require x\ge\dfrac12, so the function has domain \left[\dfrac12,\infty).

To determine the range, we need to know that, in their respective domains, \sqrt x and \log x increase monotonically without bound. We also know that x=\dfrac12 at minimum, at which point the square root term vanishes, so the least value the function takes on is \log3. Then its range would be [\log3,\infty).

3 0
3 years ago
How to figure this out!
4vir4ik [10]
96  ---> 100%

60 ----> x



x=(60*100%)/96=62.5%
5 0
3 years ago
circle 1 is centered at 4,3 and has a radius of 5 centimeters circle 2 is centered at 6,-2 and has a radius of 15 centimeters. W
wolverine [178]
We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

</span>we have that
 <span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2 
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3

radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2 

A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>


5 0
3 years ago
If P(x) = x² + x + 1 and Q(x) = 4x² - 1, find P(6).
alexandr402 [8]
43 as you substitute 6 in place of x, and then get 36+6+1=43
6 0
3 years ago
Read 2 more answers
Please answer!! It's in the exam I'm taking!! The first correct answer gets brainliest
GREYUIT [131]

Answer:

Answer B, AB is parallel to CD

Step-by-step explanation:

I'm 99% sure this is the answer.

5 0
3 years ago
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