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3 years ago

I need to find X but I don't know how to do it

Mathematics

1 answer:

klio [65]3 years ago

3 0

I think i am doing this right i am not sure. First you need to add up all the sides (100+38+22+15) it would equal 175 then you need to subtract it from 360 and get the missing value (x) then the answer would be 185

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If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$

$A2=(4)(x)=4x\ in^2$

$A3=(x)(7)=7x\ in^2$

$A4=(4)(7)=28\ in^2$

The total area of the second rectangle is the sum of the four areas

$A=A1+A2+A3+A4$

State the product of (x+4) and (x+7) as a trinomial

$(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28$

Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?

we know that

The area of the second rectangle is equal to

$A=A1+A2+A3+A4$

For x=2 in

substitute the value of x in the area of each portion

$A1=(2)(2)=4\ in^2$

$A2=(4)(2)=8\ in^2$

$A3=(2)(7)=14\ in^2$

$A4=(4)(7)=28\ in^2$

$A=4+8+14+28$

$A=54\ in^2$

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

$A(x)=x^{2} +11x+28$

For x=2 in

substitute and solve for A(x)

$A(2)=2^{2} +11(2)+28$

$A(2)=4 +22+28$

$A(2)=54\ in^2$ ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0

3 years ago

7x+6= 5(x+2)<br>help me

Zigmanuir [339]

$\huge \pink{solution}$

Given :7x+6=5(x+2)

Now We will use the distributive property to multiply 5 by x+2.

→7x+6=5x+10

We will Subtract 5x from both sides.

→7x+6−5x=10

We will Combine 7x and −5x to get 2x.

→2x+6=10

We will Subtract 6 from both sides.

2x=10−6

We will Subtract 6 from 10 to get 4.

2x=4

We will Divide both sides by 2.

x= 4/2

At last,We Divide 4 by 2 to get 2.

x=2

7 0

2 years ago

Read 2 more answers

If f(x)= 3 over x+2- square root x-3 f(19)=

PSYCHO15rus [73]

F(19)= (3/(19+2)) - sqrt(19-3)
= (3/21) - sqrt(16)
= (1/7) - 4
= (1/7) - (28/7)
= -27/7
= - 3 6/7

4 0

3 years ago

Gekata [30.6K]

Answer:

A. A(n) = 150 • (0.74)^n–1 ; 33.29 cm

Step-by-step explanation:

This is a geometric sequence.

a%5B1%5D=1.5m=150cm, r=0.74

The formula is

a%5Bn%5D=a%5B1%5Dr%5E%28n-1%29

Just substitute a1 = 150cm and r = 0.74

a%5Bn%5D=150%280.74%29%5E%28n-1%29

That's the rule.

For the second part, substitute n = 6

cm.

7 0

2 years ago

Can someone help me???

Ainat [17]

Answer:

Step-by-step explanation:

3 0

3 years ago