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Mashutka [201]
3 years ago
10

Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52

Mathematics
1 answer:
puteri [66]3 years ago
4 0

Answer:

x = 10    x = -4

Step-by-step explanation:

(x-3)^2 = 49

Take the square root of each side

sqrt((x-3)^2) =±sqrt( 49)

x-3 = ±7

Add 3 to each side

x-3+3 =3±7

x = 3+7     x = 3-7

x = 10    x = -4

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write the equation of the line that passes through the points (-4,4) and (6,9) and figure out what y=mx+b for this equation woul
jeka57 [31]
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9 - 4 / 6 - (-4)

Let's subtract. 9 - 4 is 5. 6 - (-4) is 10. 5/10 is 1/2 in simplest form. The slope for this equation is 1/2. Now, let's find the y-intercept. We will find that by plugging one of the points into the equation and solving for b. The x and y coordinates will be filled in by that coordinate. Let's use (-4, 4) for this problem. We will also plug in the slope. In this case, the problem will look like this:

4 = (1/2)(-4) + b

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6 0
4 years ago
A square plate RequalsStartSet (x comma y ): 0 less than or equals x less than or equals 1 comma 0 less than or equals y less th
larisa [96]

Answer:

Step-by-step explanation:

We are given the following:

R = \{(x,y)|0\leq x \leq 1, 0 \leq y \leq 1 \}

and T(x,y) = 100-25x - 40 y

a). Recall that a level curve of a function f(x,y) is given by R_c = \{(x,y) | f(x,y) = c\} where c is a constant. That is, all the points in the set of interest to which the function applied to the points is exactly the value c.

Consider c = 80. So we get

100-25x-40y = 80

which implies that y = \frac{-25}{40}x+0.5(Graph 1).

We can also consider c=60, which gives us

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which implies that y = \frac{-25}{40}x+1. (Graph 2)

b)Recall that the gradient of a function f(x,y) is given by

\nabla f = (\frac{df}{dx}, \frac{df}{dy})

In this case,

\frac{dT}{dx} = -25, \frac{dT}{dy} = -40

Thus, the gradient of T is given by

\nabla T =(-25,-40)

6 0
3 years ago
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