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Gnoma [55]
3 years ago
7

How do you factor 25x^2-9

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
4 0
How<span> you would factor this is,

</span>The two terms of the binomial equation 25x<span>^2 + -9 = 0 are perfect square. When factoring the difference of two perfect squares: x^2 – a^2 = (x+a)(x-a) . STEP 2: Set up and solve the equation. (5x) (5x) + (5x) (-3) + (3) (5x) + (3) (-3) = 0 With the Distributive Prop
</span><span>
PLZ IF IT HELP LIKE AND RATE!!!!

:3


</span>
hoa [83]3 years ago
3 0
If I understood the question correctly you can think of 25x^2-9 as being 25x^2+0x-9.  Therefore a=25, b=0, and c=-9.  Using the quadratic formula x=(-b(+or-)√(b²-(4ac)))/(2a).  after solving this equation with the given a, b, and c values you should get x=3/5 and -3/5.
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