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3 years ago

Graph the inequality in the coordinate plane. x > -3

Mathematics

1 answer:

Ivahew [28]3 years ago

8 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Usually, a one-variable solution set is graphed on a number line. However, since you asked for it, the attachment shows it graphed on the coordinate plane.

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The measure of c is .

mina [271]

Answer:

c^2=a^2+b^2

c^2=6^2+8^2

c^2=36+64

c=10

but still do not understand why peoples are asking that basic

4 0

3 years ago

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A rocket is launched from a tower. The height of the rocket, y in feet is related to the time after launch, x in seconds, by the

gizmo_the_mogwai [7]

Step-by-step explanation:

The height of the rocket y in feet is related to the time after launch, x in seconds, by the given equation i.e.

$y=-16x^2+165x+78$ ......(1)

It is required to find the maximum height reached by the rocket. For maximum height put $\dfrac{dy}{dx}=0$ .

So,

$\dfrac{d(-16x^2+165x+78)}{dx}=0\\\\-32x+165=0\\\\32x=165\\\\x=5.15\ s$

Put x = 5.15 in equation (1).

$y=-16(5.15)^2+165(5.15)+78\\\\y=503.39\ m$

So, the maximum height reached by the rocket is 503.39 m.

5 0

4 years ago

What is the area of this triangle?<br><br> Enter your answer in the box.

olga2289 [7]

Answer: I'm pretty sure its 12

Step-by-step explanation: You count the unit length of the base and then find the height. Now you multiply them and divide by 2.

Hope this helps.

Branliest please

7 0

3 years ago

Write the standard form equation of the circle( 7,-5)

iren [92.7K]

Answer:

(x-7)²+(y+5)²=25

Step-by-step explanation:

The standard form of a circle is (x-h)²+(y-k)²=r²

(h,k) is the center

r is the radius

h=7

k=-5

r=5

(x-7)²+(y--5)²=5²

(x-7)²+(y+5)²=25

6 0

3 years ago

What are the solutions to the equation 3x^2 + 15x = 18. Show your work.

balandron [24]

Assignment: $\bold{Solve \ Equation: \ 3x^2+15x=18}$

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Answer: $\boxed{\bold{x=1,\:x=-6}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Subtract 18 From Both Sides

$\bold{3x^2+15x-18=18-18}$

[ Step Two ] Simplify

$\bold{3x^2+15x-18=0}$

[ Step Three ] Solve With Quadratic Formula

Note: $\bold{For\:a\:quadratic\:equation\:of\:the\:form\: ax^2+bx+c=0}$

$\bold{the \ solutions \ are \ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}$

$\bold{a=3,\:b=15,\:c=-18:\quad x_{1,\:2}=\frac{-15\pm \sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}}$

<><><><><><><>

$\bold{\frac{-15+\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ 1}$

$\bold{\frac{-15-\sqrt{15^2-4\cdot \:3\left(-18\right)}}{2\cdot \:3}: \ -6}$

[ Step Four ] Combine Solutions

$\bold{x=1,\:x=-6}$

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$\bold{\rightarrow Mordancy \leftarrow}$

5 0

3 years ago

Read 2 more answers