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borishaifa [10]
3 years ago
13

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t^2 + 640

t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit.
Mathematics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

You can find the answer by using the formula x=-b/2a

Step-by-step explanation:

Remember the maximum height will be at the vertex. The x value of the vertex is your time, so use x=-b/2a. Then if it had also asked what the height was, you would plug that answer into your equation to find the y value of the vertex. Pretty sure your teacher is just asking you to find the x though:)

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Y+2=-5/4(x-4) what is the slope
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Because Point Slope Form contains m, or slope, in itself, look at the number that is multiplying the parentheses.

-5/4 is m, or slope.
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Help Not sure .. does anyone have a clue ?
denis23 [38]

Answer:

Step-by-step explanation:

f(x)=2(x+4)(x-1)

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In FGH, the measure of H=90°, HF=91 feet, and GH = 50 feet. Find the measure of F to the nearest degree.
Rudik [331]

Given:

The angle of H=90°, HF=91 feet, and GH = 50 feet.

The objective is to find the measure of angle<em> F.</em>

In the given right angled triangle, the side opposite to the requierd angle is called opposite side, and the other smaller side is called adjacent side.

The trigonometry formula which relates with the opposite and adjacent side is,

\tan \theta=\frac{opposite}{adjacent}

Now substitute the value of opposite and adjacent in the above formula to find the value of angle <em>F</em>.

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1 year ago
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Please help …………………….
Mars2501 [29]

9514 1404 393

Answer:

  (-3, 3)

Step-by-step explanation:

The blanks are trying to lead you through the process of finding the point of interest.

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The horizontal distance from T to S is <u> 9 </u>. (or -9, if you prefer)

The ratio you're trying to divide the line into is the ratio that goes in this blank:

Multiply the horizontal distance by <u> 2/3 </u>. (9×2/3 = 6)

Move <u> 6 </u> units <u> left </u> from point T.

The vertical distance from T to S is <u> 6 </u>.

Multiply the vertical distance by <u> 2/3 </u>. (6×2/3 = 4)

Move <u> 4 </u> units <u> up </u> from point T.

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Point T is (3, -1) so 6 left and 4 up is (3, -1) +(-6, 4) = (3-6, -1+4) = (-3, 3). The point that is 2/3 of the way from T to S is (-3, 3).

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