Answer:
The width of the rectangle is 5 meters, while the length of the rectangle is 12 meters.
Step-by-step explanation:
Given that the perimeter of a rectangle is twice the sum of its lenght and its width, and the perimeter is 34 meters and its lenght is 2 meters more than twice its width, to determine the length and width of the rectangle the following calculation must be done:
(2X + 2 + X) x 2 = 34
(3X + 2) x 2 = 34
6X + 4 = 34
6X = 34 - 4
X = 30/6
X = 5
(2x5 + 2 + 5) x 2 = 34
(10 + 2 + 5) x 2 = 34
17 x 2 = 34
34 = 34
Therefore, the width of the rectangle is 5 meters, while the length of the rectangle is 12 meters.
Answer:
∠KMN = 66°
Step-by-step explanation:
In ΔKMN,
∠MKN + ∠KNM + ∠KMN = 180 {Angle sum property of triangle}
39 + 75 + ∠KMN = 180
114 + ∠KMN = 180
∠KMN = 180 - 114
∠KMN = 66°
Answer:
- AP
- tₙ = (n-2)k² + (2n - 3)k + n
Step-by-step explanation:
<u>Given sequence:</u>
- -k² - k + 1, k + 2, k² + 3k + 3, 2k² + 5k + 4, ...
We can see apart from the second term all terms are 2nd degree trinomial so it is not a GP.
Let's find the difference: to determine if it is a AP:
- k + 2 - (-k² - k + 1) = k + 2 + k² + k -1 = k² + 2k + 1
- k² + 3k + 3 - (k + 2) = k² + 3k + 3 - k - 2 = k² + 2k + 1
- 2k² + 5k + 4 - (k² + 3k + 3) = 2k² + 5k + 4 - k² - 3k - 3 = k² + 2k + 1
As we see the difference is common and it confirms the sequence is AP.
<u>First term is </u>
<u>Common difference is </u>
<u>nth term is:</u>
- tₙ = a₁ + (n-1)d
- tₙ = -k² - k + 1 + (n-1)(k² + 2k + 1) =
- -k² - k + 1 + (n-1)k² + (n-1)*2k + n-1 =
- (n-2)k² + (2n - 3)k + n
The picture wouldn't fit but the first step was to multiply the denominators by 8
the answer is -11/2
You said that 51 + (the other number) = 136 .
This is an equation.
I can do anything I want to one side of it,
as long as I do exactly the same thing to
the other side.
Let's subtract 51 from each side: (the other number) = 136 - 51
= 85 .
The factors of 51 are 1, 3, 17, and 51 .
The factors of 85 are 1, 5, 17, and 85 .
The common factors are 1 and 17 .
