Answer:
System of equations:
Augmented matrix:
![\left[\begin{array}{cccc}1&2&2&6\\2&1&1&6\\1&1&3&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C2%261%261%266%5C%5C1%261%263%266%5Cend%7Barray%7D%5Cright%5D)
Reduced Row Echelon matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%261%261%262%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Convert the system into an augmented matrix:
For notation, R_n is the new nth row and r_n the unchanged one.
1. Operations:
Resulting matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&-3&-3&-6\\0&-1&1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%26-3%26-3%26-6%5C%5C0%26-1%261%260%5Cend%7Barray%7D%5Cright%5D)
2. Operations:
Resulting matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&-1&1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%261%261%262%5C%5C0%26-1%261%260%5Cend%7Barray%7D%5Cright%5D)
3. Operations:
Resulting matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%261%261%262%5C%5C0%260%262%262%5Cend%7Barray%7D%5Cright%5D)
4. Operations:
Resulting matrix:
Answer:
in the chapter 7 in class 9 Ex 7.3
one time - and second time +
Step-by-step explanation:
x-2=4+x
1) x-2=-(4+x)
x-2=-4-x
x+x=-4+2
2x=-2
x=-2/2
x=-1
2) x-2=4+x
=0
<u><em>Answer</em></u>
= 3.405 × 10⁻⁴
<u>Explanation</u>
If the question is correctly written, then it is very easy.
First, take the like terms on one side.
493x = 3432x+1
493x - 3432x = 1
-2939x = 1
Dividing both sides by -2939 to get the value of x.
x = 1/(-2939)
= - 0.0003405
= 3.405 × 10⁻⁴
Answer:
4/500
Step-by-step explanation:
