Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20
(x - a)(x - b) = 0
(x - (-2))(x - (-10)) = 0
(x + 2)(x + 10) = 0
x^2 + 10x + 2x + 20 = 0
x^2 + 12x + 20 = 0
-h = 12
h = -12
4k = 20
k = 5
Answer:
4(x -
)² = 0
Step-by-step explanation:
Given
4x² - 4x + 1 = 0
To complete the square the coefficient of the x² term must be 1
Factor out 4 from 4x² - 4x
= 4(x² - x) + 1 = 0
add/subtract ( half the coefficient of the x- term )² to x² - x
4(x² + 2(-
)x +
-
) + 1 = 0
4(x -
)² - 1 + 1 = 0
4(x -
)² = 0
Answer:
A.) Both lines pass through the point represented by the ordered pair
Step-by-step explanation:
First get y by its self , then graph , find intersection point and plug in x and y to both equations, see if it makes sense , then the solution must be you intersection point