Question

The drama club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $5.50 and bags of cookies cost $3.50, and the sales total was $53.50. There were 5 more bags of cookies sold than candy. Find the number of bags of candy and cookies sold by the drama club.

Answer 1

Let's assume

the number of bags of candy =x

the number of bags of cookies =y

There were 5 more bags of cookies sold than candy

so, we get

$y=x+5$

Bags of candy cost $5.50

so, total cost of candy is

$=5.50x$

bags of cookies cost $3.50

so, total cost of cookies is

$=3.50y$

so,

total cost = (total cost of candy)+(total cost of cookies)

we get

total cost =5.50x+3.50y

so, we can plug

$5.50x+3.50y=53.50$

now, we can plug y

$5.50x+3.50(x+5)=53.50$

$5.5x\cdot \:10+3.5\left(x+5\right)\cdot \:10=53.5\cdot \:10$

$55x+35\left(x+5\right)=535$

$55x+35x+175=535$

$90x+175=535$

$90x+175-175=535-175$

$90x=360$

$x=4$

now, we can find y

$y=x+5$

$y=4+5$

$y=9$

so,

the number of bags of candy =4

the number of bags of cookies =9............Answer