Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
thats the answer just look at the picture :)
for the work
Answer:
7/10 or 70%
Step-by-step explanation:
There has to be at least two T in each result of the simulation. This means you can also have 3 T's and 4 T's in the result.
These are the results that qualify as having at least two T's.
1. TTTT, 2. TTTT, 3. THTH, 4. HTTT, 5. TTTT, 7. HTHT, 9. THTH
That is 7 out of the 10 results which is 7/10 or 70%
Answer:
15
Step-by-step explanation:
8.25 minus 7.80 is 0.45 45 divided by 3 is 15 so the answer is 15
Answer:
Leg1 = 9 and leg2 = 12
Step-by-step explanation:
<u>Points to remember</u>
<u>Pythagorean theorem</u>
Hypotenuse² = Base² + Height²
<u>To find the length of each leg</u>
It is given that, hypotenuse = 15 feet
Let base = x the height = x +3
By using Pythagorean theorem we can write,
Hypotenuse² = Base² + Height²
15² = x² + (x + 3)²
225 = x² + x² + 6x + 9
2x² + 6x + 216 = 0
x² + 3x + 108 = 0
By solving we get x = 9 and x -12
Therefore one leg = 9 and other leg = 9 + 3 = 12