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STALIN [3.7K]
3 years ago
10

The graph of the function g(x) is a transformation of the parent function f(x)=x2.

Mathematics
1 answer:
adoni [48]3 years ago
6 0
Answer:
g(x)=x2-4

explanation:
the graph of g is the graph of f shifted down 4
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6 = 14 - x <br> One step equations review
Ymorist [56]

Answer:

x = 8

Step-by-step explanation:

6 = 14 - x

chance the equation around so it is solvable

14 - x = 6

14 - 6 = x

now solve

14 - 6 = 8

that means x equals 8 so

6 = 14 - 8

4 0
3 years ago
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The coordintates of 2 vertices arae A (-2,5), and B(5,-3). What could be the other vertices to this right triangle?
Alecsey [184]
The other vertices are (-2,5).
6 0
3 years ago
HELP. there are 45 coins consisting of nickels, dimes and quarter making a total of 7 dollars. the number of dimes exceeds the n
MA_775_DIABLO [31]

9514 1404 393

Answer:

  20

Step-by-step explanation:

Let n, d, q represent the numbers of nickels, dimes, and quarters, respectively. Then we have ...

  n + d + q = 45

  5n +10d +25q = 700

  n -d = -5

__

Using n=d -5, we can substitute into the first two equations:

  (d -5) +d + q = 45

  2d +q = 50 . . . . add 5, collect terms [eq4]

__

  5(d -5) +10d +25q = 700

  15d +25q = 725 . . . . . . . . . . add 25, collect terms [eq5]

Multiplying [eq4] equation by 3 and subtracting that from 2/5 of [eq5], we have ...

  (2/5)(15d +25q) -3(2d +q) = (2/5)(725) -3(50)

  6d +10q -6d -3q = 290 -150

  7q = 140 . . . . . . simplify

  q = 20 . . . . . . . . divide by 7

There are 20 quarters.

8 0
3 years ago
Which number gives you an irrational product when you multiply it by 0.2?
Eddi Din [679]

Answer:

C

Step-by-step explanation:

5 0
3 years ago
Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne
Pavlova-9 [17]

Answer:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

p_v =P(t_{(15)}>1.507)=0.076

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

\bar X_{CTS}=2.35 represent the mean for the sample CTS

\bar X_{N}=1.83 represent the mean for the sample Normal

s_{CTS}=0.88 represent the sample standard deviation for the sample of CTS

s_{N}=0.54 represent the sample standard deviation for the sample of Normal

n_{CTS}=10 sample size selected for the CTS

n_{N}=7 sample size selected for the Normal

\alpha=0.01 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis:\mu_{CTS} \leq \mu_{N}

Alternative hypothesis:\mu_{CTS} > \mu_{N}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{CTS}+n_{N}-2=10+7-2=15

Since is a one side right tailed test the p value would be:

p_v =P(t_{(15)}>1.507)=0.076

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

6 0
4 years ago
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