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never [62]
2 years ago
15

Calculate the length of the circumference of a circle with radius of 7cm

Mathematics
2 answers:
borishaifa [10]2 years ago
7 0
The circumference should be 43.98
lions [1.4K]2 years ago
7 0
14 x pie or just 14pie.
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If the r-value, or correlation coefficient, of a data set is 0.908, what is the coefficient of determination to three decimal pl
belka [17]
0.824.....Apex if answer changed not my fault but kinda helpful
5 0
3 years ago
Read 2 more answers
Help me find the area of this circle
ch4aika [34]
The area would be approximately 153.94.

The area of a circle is pie multiplied by r^2. 

So you have the radius, which is r. Plug in r. Technically you have two numbers because pie equals approximately 3.14.

A=3.14(7)^2 
3 0
2 years ago
A parallelogram with the sides of 6 and 10 has a area of 30 square root of 2. Find the measure of each angle of the parallelogra
Vinvika [58]
a=10,b=6,A=30 \sqrt{2} 
\\
\\A=ah_a=ab\sin\theta
\\30 \sqrt{2} =10\times6\times\sin\theta
\\
\\ \sin\theta= \frac{ \sqrt{2} }{2} 
\\
\\ \theta=45^o
\\ \theta_1=180^o -\theta=180^o-45^o=135^o

7 0
2 years ago
Read 2 more answers
Please help and thank you
zubka84 [21]

Answer:

B

Step-by-step explanation:

The graph of x² is known as the parent function. From it, all quadratics can be transformed to make their graphs. It can undergo a series of transformations like translations up/down/left/right or stretch and compression vertically and horizontally. Usually the equation can tell you you what transformations it undergoes. Since g(x) is the same equation as x² except for 4/5 this is a vertical compression. Since it is the leading coefficient under multiplication and 4/5 < 1, this is a compression vertically. Answer B is correct.

8 0
2 years ago
The graph of f(x) = x3 − 7x − 6 is shown. Based on the graph, what are all of the solutions to f(x) = x3 − 7x − 6? x = −6 x = −2
pogonyaev
F(x)=x^3-7x-6  Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P

x-(f(x)/(dy/dx))

x-(x^3-7x-6)/(3x^2-7)

(2x^3+6)/(3x^2-7), letting x1=0

0, -6/7, -.988, -.9999, -.99999999999, -1

(x^3-7x-6)/(x+1)

x^2 r -x^2-7x-6
-x   r  -6x-6
-6   r  0

(x+1)(x^2-x-6)=0

(x+1)(x-3)(x+2)=0

x= -2, -1, 3 


4 0
3 years ago
Read 2 more answers
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