Answer:
1.14 s
Step-by-step explanation:
Time, 
Here, d is the distance and s is the speed/velocity
Since we're given the velocity, s as 28 ft/s and the distance between the position of the rocket and ground as 32 ft then
Therefore, it needs 1.14 seconds
Answer:
x = 17
Step-by-step explanation:
8x - 9 + 53 = 180 (collect like terms)
8x + 44 = 180 (subtract 44 on both sides)
8x = 136 (divide by 8 on each side)
x = 17
HOpe this helps!!
Answer:
Y= 2e^(5t)
Step-by-step explanation:
Taking Laplace of the given differential equation:
s^2+3s-10=0
s^2+5s-2s-10=0
s(s+5)-2(s+5) =0
(s-2) (s+5) =0
s=2, s=-5
Hence, the general solution will be:
Y=Ae^(-2t)+ Be^(5t)………………………………(D)
Put t = 0 in equation (D)
Y (0) =A+B
2 =A+B……………………………………… (i)
Now take derivative of (D) with respect to "t", we get:
Y=-2Ae^(-2t)+5Be^(5t) ....................... (E)
Put t = 0 in equation (E) we get:
Y’ (0) = -2A+5B
10 = -2A+5B ……………………………………(ii)
2(i) + (ii) =>
2A+2B=4 .....................(iii)
-2A+5B=10 .................(iv)
Solving (iii) and (iv)
7B=14
B=2
Now put B=2 in (i)
A=2-2
A=0
By putting the values of A and B in equation (D)
Y= 2e^(5t)
