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lys-0071 [83]
3 years ago
11

The blue segment below is a radius of o. what is the length of the diameter of the circle

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0

Answer:

The length of the diameter of circle  is 18.6 units

Step-by-step explanation:

Given : Radius of circle(r) = 9.3 units

To Find : The diameter of a given circle

Solution :

Definition of Diameter : It is a straight line segment  whose endpoints lie on the circle that passes through the center of the circle . It is the longest chord . It is the twice of the radius .

Using the property ( Diameter is twice of radius )

Since radius of circle (r) is 9.3 units

Thus diameter :


2*r


⇒2*9.3


⇒18.6


Hence the length of the diameter  is 18.6 units .

fgiga [73]3 years ago
4 0
The answer is D. 18.6 units.
The radius is half the diameter so to find the diameter you would simply multiply the radius by 2.
Hence: 9.3*2=18.6
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What is the distance between the points (21,-30) and (3,8)
Scilla [17]

Answer:

approximately 42.05

Step-by-step explanation:

We know that the distance formula is \sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} }, so if we use (3,8) as point 2 and (21, -30) as point 1 (note that these are interchangeable), we know that

x₂=3

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x₁=21

y₁=-30

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5 0
3 years ago
If the endpoints of segment AB are A(-4,5) and B(2,-5),<br><br>please help! ​
nadezda [96]

Answer:

d = \sqrt[2]{34}

Step-by-step explanation:

We are solving for the segment of AB. Note that it is a line segment, so there will be end points, those being A(-4, 5) & B(2, -5).

Use the following distance formula:

<em />distance<em> </em>(d) = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - x_{2})^2 }

Let:

Point B(2 , -5) = (x₁ , y₁)

Point A(-4 , 5) = (x₂ , y₂)

Plug in the corresponding numbers to the corresponding variables.

d = \sqrt{(-4 - 2)^{2} + (5 - (-5))^{2} }

Simplify. Remember to follow PEMDAS. First, solve the parenthesis, then the powers, then add, and then finally square root.

d = \sqrt{(-6)^{2} + (5 + 5)^{2}  } \\d = \sqrt{(-6 * -6) + (10)^2} \\d = \sqrt{(36) + (10 * 10)} \\d = \sqrt{36 + (100)} \\d = \sqrt{136}

Simplify:

d = \sqrt{136} = \sqrt{2 * 2 * 2 * 17}  = \sqrt[2]{17 * 2} = \sqrt[2]{34}

d = \sqrt[2]{34} is your answer.

~

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3 years ago
What is the slope-intercept equation of the line below
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It would be A to this question
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