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tamaranim1 [39]
3 years ago
9

If x equals 3, calculate the value of x times x subtracted by x

Mathematics
2 answers:
Zepler [3.9K]3 years ago
7 0
I think the answer in this is 6.
saul85 [17]3 years ago
5 0
3*3=9

9-3= 6

your answer is 6
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Write a fraction that is equivalent to 2/3.
Sphinxa [80]
8/12 is a fraction that is equivalent to 2/3.When simplified, the answer is 2/3 and when you multiply numerator and denominator by 4, the answer is 8/12

6 0
3 years ago
Graph y = 2x + 5.<br> Need help ASAP plz and thank you
soldi70 [24.7K]

Answer:

*see graph below*

Step-by-step explanation:

y = mx + b

m = slope (rise over run)

b = y-intercept

Corresponding with the given equation, the graph below has a y-intercept of 5, and a slope of \frac{2}{1} or 2.

8 0
2 years ago
Read 2 more answers
Can someone help me please ?
denis-greek [22]
It is the one second from the top. the line is straight (y=-3) until it hits x=-1 then it starts increasing significantly
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Ber [7]

Answer:

-3x + 36

it is correct answer

4 0
3 years ago
A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0
3 years ago
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