The answer to your question is(1,2)
Answer:
Hope this helped. A brainliest would be very much appreciated. (I need 4 brainliest so I can level up) :)
There may be more than one way in which to answer this question. I will assume that the "equation" is a linear one: f(x) = mx + b.
Then (16/3) = m(1) + b
This is one equation in two unknowns, so it does not have a unique solution. Was there more to this problem than you have shared?
If we assume that the y-intercept (b) is zero, then y = mx, and
16/3 = 1m, so that m = 16/3, and so y = (16/3)x.
Answer: No, it is not a solution
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Explanation:
The point (3,-4) means that x = 3 and y = -4 pair up together
Let's plug these x,y values into each equation
Starting with the first equation, we get,
y = 4x-16
-4 = 4(3)-16 ... x replaced with 3; y replaced with -4
-4 = 12-16
-4 = -4 .... this is a true statement
Repeat for the second equation
y = 2x-6
-4 = 2(3)-6
-4 = 6-6
-4 = 0 ... this is false
Since we get a false statement, this means (3,-4) is not on the line y = 2x-6, which means that overall (3,-4) is not a solution to the system of equations. The point (3,-4) must make both equations true for it to be a solution.
Answer:
correct
Step-by-step explanation:
