1)
∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰
AB = 370 m
AC = 510 m
To find BC we can use cosine law.
a² = b² + c² -2bc*cos A
|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)
|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =
|BC| ≈ 553 m
2)
To find ∠ACB, we are going to use law of sine.
sin(∠BAC)/|BC| = sin(∠ACB)/|AB|
sin(76⁰)/553 m = sin(∠ACB)/370 m
sin(∠ACB)=(370*sin(76⁰))/553 =0.6492
∠ACB = 40.48⁰≈ 40⁰
3)
∠BAC = 76⁰
∠ACB = 40⁰
∠CBA = 180-(76+40) = 64⁰
Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰
4)
Shortest distance from A to BC is height (h) from A to BC.
We know that area of the triangle
A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).
Also, area the same triangle
A= (1/2)|BC|*h = (1/2)*553*h.
So, we can write
(1/2)*370*510*sin(76⁰) =(1/2)*553*h
370*510*sin(76⁰) =553*h
h= 370*510*sin(76⁰) / 553= 331 m
h=331 m
Answer:
150
Step-by-step explanation:
3 times 50 equal 150
Answer:
The answer would be C
Step-by-step explanation:
He started at 250 lbs. He is losing 3 lbs every week.
So it would be y=250(beginning weight)-3x(how much he's losing every week)
Hope this helped :)
×=y/3-z/3+3 thats the x value in this equation
Answer:
option (b) 0.0228
Step-by-step explanation:
Data provided in the question:
Sample size, n = 100
Sample mean, μ = $20
Standard deviation, s = $5
Confidence interval = between $19 and $21
Now,
Confidence interval = μ ± 
thus,
Upper limit of the Confidence interval = μ + 
or
$21 = $20 + 
or
z = 2
Now,
P(z = 2) = 0.02275 [From standard z vs p value table]
or
P(z = 2) ≈ 0.0228
Hence,
the correct answer is option (b) 0.0228