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Salsk061 [2.6K]
3 years ago
6

Arrange 2/3, 3/5, 5/7 in order from least to greatest?

Mathematics
2 answers:
liq [111]3 years ago
6 0
The easiest way for me to do this, as I suck at fractions, is to divide. so 2/3 would be 0.66(repeating) 3/5 would be 0.6 and 5/7 is 0.714, Saying that, the answer is 3/5, 2/3, 5/7. 0.6 is two numbers, 9 and 6, while 0.66 repeating has endless numbers, making it greater than 0.6 non repeating. Hope this helped!
AveGali [126]3 years ago
3 0
3/5
2/3
5/7
top is least bottom is greatest
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Answer:

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Step-by-step explanation:

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3 years ago
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I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.

</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
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2 years ago
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Please help!! MathsWatch, Surd Expressions, Clip 207c
dexar [7]

Answer:

A=(72+36\sqrt{3})\ mm^2

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

b=AB+BC+CD+DE ----> by segment addition postulate

substitute

b=3+3+3+3=12\ mm

step 2

Find the height of rectangle

a=FB+CG+GH ---> by segment addition postulate

substitute the given values

a=3+CG+3\\a=6+CG

Find the length sides CG

Applying the Pythagorean Theorem

BG^2=BC^2+CG^2

substitute the given values

6^2=3^2+CG^2

CG^2=6^2-3^2

CG=\sqrt{27}\ mm

simplify

CG=3\sqrt{3}\ mm

therefore

a=(6+3\sqrt{3})\ mm

step 3

Find the area of rectangle

A=ab

we have

a=(6+3\sqrt{3})\ mm

b=12\ mm

substitute

A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2

8 0
3 years ago
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andreyandreev [35.5K]
Okay! 4/16= 0.25 because  16/16 = 1 and so that means 12/16 = 0.75   and 8/16 = 0.50 and 4/16 = 0.25   Hope this helped!
4 0
3 years ago
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