Answer:
9 times as many as 3 is 27.
Step-by-step explanation:
Answer:
AE = 15 cm; ED = 18 cm; AD = 15 cm (given)
Step-by-step explanation:
ΔBEC ~ ΔAED so ...
AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE
Substituting given numbers (lengths in centimeters), we have ...
15/10 = 1 + 5/BE
1/2 = 5/BE
BE = 10
Similarly, ...
1/2 = 6/CE
CE = 12
Then the unknown sides are ...
AE = AB + BE = 5 + 10 = 15 . . . cm
ED = CE + CD = 12 + 6 = 18 . . . cm
The table is attached in the figure.
g(x) = f(4x) ⇒⇒⇒ differentiating both sides with respect to x
∴ g'(x) = ![\frac{d}{dx} [f(x)] * \frac{d}{dx} [4x]=4*f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29%5D%20%2A%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B4x%5D%3D4%2Af%27%28x%29)
⇒⇒⇒⇒⇒⇒ chain role
To find g '(0.1)
Substitute with x = 0.1
from table:
f'(0.1) = 1 ⇒ from the table
∴ g'(0.1) = 4 * [ f'(0.1) ] = 4 * 1 = 4
