Y = 2^x and y = log₂x
Exponents and logs (to the same base = 2) are inverses of each other.
All inverse functions are symmetric about line y = x
y = log₂x is NOT the logarithmic form of y = 2^x
The logarithmic form of y = 2^x is x = log₂y (NOT y = log₂x)
Answer: A, C
Answer:
(b+1)(b²+1)
Step-by-step explanation:
51/22 hope this helps BRAINLIEST??
Answer:
<h2>90</h2>
Step-by-step explanation:
Substitute a = -3 and b = -8 to the expression 10a²b⁰:
10(-3)²(-8)⁰ = 10(9)(1) = 90
a⁰ = 1 for any real number
