Which value must be added to the expression x2 + 12x to make it a perfect-square trinomial?
2 answers:
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<h2>Explanation:</h2><h2></h2>
Here you haven't provided any function, so I'll assume this one:
This is a quadratic function whose graph represents a parabola. Any parabola has its vertex at the point:
Therefore:
Therefore, the vertex is:
The perpendicular line will have the x and y coefficients swapped and one of them negated. We can write the desired line as
9(x -6) -3(y -4) = 0
where the coordinates of the point of interest are (6, 4).
Dividing by 3, this is
3(x -6) -(y -4) = 0
3x -y = 14
An equation for the line of interest is ...
3x -y = 14
9(x -6) -3(y -4) = 0
where the coordinates of the point of interest are (6, 4).
Dividing by 3, this is
3(x -6) -(y -4) = 0
3x -y = 14
An equation for the line of interest is ...
3x -y = 14