Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
x≤−3
Interval Notation: ( − ∞ , − 3 ]
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
They have 1.4 bags of popcorn.
1) 9 7/8
2) 2 yd
3) 58
Answer:
If x is 2, then the function returns x squared or 4.
Step-by-step explanation:
To find this, just plug the numbers into the expressions.
5x = y
5(2) = 7
10 = 7
So it can't be A.
x + 2 = y
2 + 2 = 7
4 = 7
x + 4 = y
2 + 4 = 7
6 = 7
2x + 3 = y
2(2) + 3 = 7
7 = 7
The correct answer is
D. 2x + 3
