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Serjik [45]
3 years ago
9

Calculate population variance from population standard deviation

Mathematics
1 answer:
Tema [17]3 years ago
8 0
The standard deviatiion is the square root of the variance.
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1/2(a+b)-(a-b)exponent2 when a=18 and b=14
lora16 [44]

Answer:

0

Step-by-step explanation:

Substitute the given values for a and b into the expression

\frac{1}{2}(18 + 14) - (18 - 14)²

= \frac{1}{2} × 32 - 4²

= 16 - 16

= 0

8 0
3 years ago
You are given the dollar value of a product in 2015 and the rate at which the value of the product is expected to change during
Charra [1.4K]

Answer:

V = $3.50t + $90.5....

Step-by-step explanation:

V(t) is a function of t that expresses the value in year 2000+t.  

We know that the increase is $3.50 times t.

So,

V(t) = $3.50t + c  

where c is the constant.

V(15) =  $3.50 (15) + c = $143     [t=15 as mentioned in the question]

and therefore  

c = $143 - $3.50 (15)

c= $143 - $52.50

c= $90.5  

Now we got the value of c. We can write the equation as  

V = $3.50t + $90.5....

4 0
3 years ago
Can you help me please?
Kamila [148]

Answer: The set of all possible input values

Step-by-step explanation:

7 0
3 years ago
For the graphed exponential equation, calculate the average rate of change from x = -3 to x = 0
Dimas [21]

The answer to the question is D.

3,2 was your first point and it dropped to -5,0.

3 0
3 years ago
Plzz help me im going to most more like this because im not understanding it
lisov135 [29]
Hi there!

In order to solve, you can use substitution. This means that you use one equation and solve for one variable, then use that one equation and plug it into the other equation. Here's how we'd do it:

WORK:
x = 12 - y (since x is already solved for, we'll use that to plug into the other given equation.
2(12 - y) + 3y = 29 (using substitution)
24 - 2y + 3y = 29
24 + y = 29
y = 5
Plug the value of y back into the first equation
x = 12 - 5
x = 7

ANSWER:
A - x = 7, y = 5

It seems as though you're having some trouble with these questions, PLEASE MESSAGE ME!! I'd be more than happy to help you work through as many problems as you need until you get the hang of it (plus, it doesn't cost you any points!)

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
5 0
4 years ago
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