Please answer both parts, will give first answer brainliest

Tain has a great literary tradition that spans centuries. One might assume, then, that Britons read more than citizens of other

tresset_1 [31]

Answer:

Null hypothesis: $p_{1} \leq p_{2}$

Alternative hypothesis: $p_{1} > p_{2}$

$z=3.02$

$p_v =P(Z>3.02)=0.00127$

The p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of Canadians is not significantly higher than the porportions of readers at Britons.

Step-by-step explanation:

1) Data given and notation

$X_{1}=0.86*1004$ represent the number of Canadians randomly sampled by Gallup that read at least one book in the past year

$X_{2}=0.81*1009$ represent the number of Britons randomly sampled that read at least one book in the past year

$n_{1}=1004$ sample of Gallup selected

$n_{2}=1009$ sample of Britons selected

$p_{1}=0.86$ represent the proportion of Canadians randomly sampled by Gallup that read at least one book in the past year

$p_{2}=0.81$ represent the proportion of Britons randomly sampled that read at least one book in the past year

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion for men with red/green color blindness is a higher than the rate for women , the system of hypothesis would be:

Null hypothesis: $p_{1} \leq p_{2}$

Alternative hypothesis: $p_{1} > p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{0.81+0.86}{2}=0.835$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.86-0.81}{\sqrt{0.835(1-0.835)(\frac{1}{1004}+\frac{1}{1009})}}=3.02$

4) Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =P(Z>3.02)=0.00127$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of Canadians is not significantly higher than the porportions of readers at Britons.

5 0

4 years ago

20 pts if correct and will mark brainliest

guapka [62]

Answer:

1/4

Step-by-step explanation:

the chance of getting an odd number is 3/6 or 1/2

the chance of heads is 1/2

1/2* 1/2= 1/4

5 0

4 years ago

Read 2 more answers

How do you show 28 X 20 on a visual model (pls show with dots) (ASAP)

SSSSS [86.1K]

1 2 and you would keep going until you had 20 rows
.... .... of 28
.... ....
.... ....
.... ....
.... ....
.... ....
....
....

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=15%20%2B%205x%20%20%5C%5C%2014x%20-%206" id="TexFormula1" title="15 + 5x \\ 14x - 6" alt="15

olga_2 [115]

Reorder the terms:

6 + 14x = 15x

Solving

6 + 14x = 15x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-15x' to each side of the equation.

6 + 14x + -15x = 15x + -15x

Combine like terms: 14x + -15x = -1x

6 + -1x = 15x + -15x

Combine like terms: 15x + -15x = 0

6 + -1x = 0

Add '-6' to each side of the equation.

6 + -6 + -1x = 0 + -6

Combine like terms: 6 + -6 = 0

0 + -1x = 0 + -6

-1x = 0 + -6

Combine like terms: 0 + -6 = -6

-1x = -6

Divide each side by '-1'.

x = 6

Simplifying

x = 6

4 0

4 years ago

Help please!! Brainliest Answer! Suppose that in one day, a theme park had 1,200 visitors. One fourth of those visitors were ov

velikii [3]

300 people, I think. One fourth of 1,200 is 300.

3 0

3 years ago