s = hours it takes the small pipe on its own.
L = hours it takes the large pipe on its own.
we know the small pipe can do it in 11 hours total, so s = 11, so, how much of the whole job has the small done in 1 hour only?
well, if it takes 11 hours to do the whole thing, in 1 hour it has done only 1/11 of the whole job.
we know both pipes working together can do it in 6 hours flat. So in 1 hour only, both of them have done only 1/6 of the whole thing.
in that 1 hour, how much has the large one done? well, it has only done 1/L of the job.

and you can round that up as needed.
Answer:
Step-by-step explanation:
Area of a Segment in Radians A = (½) × r2 (θ – Sin θ)
Area of a Segment in Degrees A = (½) × r 2 × [(π/180) θ – sin θ]
Answer:
<em>radius: r2 = 3.14 × 632 = 12470 square mm</em>
Step-by-step explanation:
Huh? What does that even mean lol
Hello
<span>D. 2 imaginary roots (complex conjugates)</span>