6x-2y=24 how do u solve for y
2 answers:
It's <span>Diophantine equation.
First, we need to found gcd(6,(-2)):</span>
6=2*3
(-2)=(-1)*2
So, gcd(6,-2)=2
Now, the question is. Can we dived c=24, by gcd(6,-2) and in the end get integer?
Yes we can.
So, we can solve it.
Now is the formula:
Second, we need the first pair (x0,y0)
if
x=0
then
Third, we gonna use that formula:
Congratulations! We solve it.
First, we need to found gcd(6,(-2)):</span>
6=2*3
(-2)=(-1)*2
So, gcd(6,-2)=2
Now, the question is. Can we dived c=24, by gcd(6,-2) and in the end get integer?
Yes we can.
So, we can solve it.
Now is the formula:
Second, we need the first pair (x0,y0)
if
x=0
then
Third, we gonna use that formula:
Congratulations! We solve it.
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Answer:
0.35% of students from this school earn scores that satisfy the admission requirement.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.
This means that
The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?
The proportion is 1 subtracted by the pvalue of Z when X = 2294. So
has a pvalue of 0.9965
1 - 0.9965 = 0.0035
0.0035*100% = 0.35%
0.35% of students from this school earn scores that satisfy the admission requirement.
Answer: The correct option is (A) reduction.
Step-by-step explanation: Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.
As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:
AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.
And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:
We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.
Now, the scale factor is given by
Since the scale factor is less than 1, so the dilation will be a reduction.