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adelina 88 [10]
4 years ago
10

Brainliest question please help please help me now plz

Mathematics
1 answer:
mezya [45]4 years ago
5 0

Answer:

13/b I think

Step-by-step explanation:

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I NEED THE ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br><br><br><br><br> 1/7-3(3/7x-2/7)
melomori [17]

Step-by-step explanation:

x in (-oo:+oo)

1/7-(3*((3/7)*x-(2/7))) = 0

1/7-3*((3/7)*x-2/7) = 0

1/7-3*(3/7*x-2/7) = 0

(-3*7*(3/7*x-2/7))/7+1/7 = 0

1-3*7*(3/7*x-2/7) = 0

7-9*x = 0

(7-9*x)/7 = 0

(7-9*x)/7 = 0 // * 7

7-9*x = 0

7-9*x = 0 // - 7

-9*x = -7 // : -9

x = -7/(-9)

x = 7/9

x = 7/9

6 0
3 years ago
Read 2 more answers
The following dot plot represents a random sample of elementary students and the number of children that live in their home.
NISA [10]

1.

None of the households in the United States contain five children.

2.

The majority of the households in the United States, with at least one child, contain less than three children.

If thats wrong dont go off on me

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~Mia for short~

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
Olivia places her pet frog on a line to observe the frog’s motion. The line is divided into sections that measure 1 centimeter e
zvonat [6]

Answer: 0

Explanation: Displacement is how far something or someone is from the starting point, in this case, the frog, so it moves 18F then 6B then 12B, so 0+18-6-12=0.

Hope this helps! :)

4 0
3 years ago
8•x + 10 +2x +4 •x + 8 -6
Tcecarenko [31]

Answer:

14x + 12

Step-by-step explanation:

8 times x would be 8x

4 times x would be 4x

8x+10+2x+4x+8-6

8x+2x+4x=14x

10+8-6=12

=14x + 12

5 0
3 years ago
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