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inessss [21]
3 years ago
11

5/8 + 11/12 in fraction simplified in simplest form

Mathematics
2 answers:
Katarina [22]3 years ago
7 0
You need to get the lowest common denominator first, this would be 24 (8 x 3 and 12 x 2)
So multiple he top and bottom to get the denominator to 24
For 5/8: 5 x 3 = 15 and 8 x 3 = 24
For 11/12: 11 x 2 = 22 and 12 x 2 - 24
so you have 15/24 and 22/24 
Then you add the numerators together 15 + 22 = 37, to become 37/24 and because 37 is prime 37/24 is simplest terms

Korolek [52]3 years ago
6 0

oooooooooooooooooooooo

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d = 17

Step-by-step explanation:

The given arithmetic sequence is :

31, 48, 65, 82, ...

We need to find the common difference for this sequence.

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Second term, a₂ = 48

Common difference = a₂-a₁

= 48-31

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So, the common difference for this arithmetic sequence is equal to 17.

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3 years ago
Mr. Shively’s TV cabinet is 30 inches tall and 40 inches wide. Best Buy is selling 50 inch, 55 inch, 60 inch, and 65 inch TVs. O
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He should buy a 50 inch TV

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3 years ago
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2 years ago
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spayn [35]
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Long answer: The definition of a "Geometric Sequence" is available, for instance, at http://www.mathsisfun.com/algebra/sequences-sums-geometric.html : "<em>In a Geometric Sequence each term is found by multiplying the previous term by a constant."


</em>In this case, you are given the first term (43), and the third term (2107) and you have one missing term, specifically the second term. If you divide the third term (2107) by the first term (43) then you get 49. And you know that 49 = 7 * 7. So, you reach the conclusion that you can multiply the first term (43) by 7 to get to the missing term and that you can multiply that missing term again by 7 to get to the third term (2107). That satisfies our "Geometric Sequence" requirement that each term is multiplied by a constant (the constant is 7, in this case).

So, if you multiply 43 by 7, you get 301 (the missing second term). And if you multiplied 301 again by 7 then you would get to the third term that was given in the question (2107).
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3 years ago
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