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2 years ago

Write the equation of the line with an x-intercept at (0,2) and perpendicular to 3x+4y=12.

Mathematics

2 answers:

Deffense [45]2 years ago

8 0

The answer is y=4/3+2

juin [17]2 years ago

6 0

First you normalize 3x+4y=12 into y = -3/4 x + 3 (dividing by 4).

Then you observe that the slope of the line is -3/4 (it's always the factor with the x). A perpendicular line has the reciprocal slope. Reciprocal means inverted and negated. So -3/4 becomes +4/3.

The equation will thus look like y = 4/3 x + b. To find b, we fill in the given x intercept (0,2), (we get 2 = 4/3 * 0 + b). With x=0, b must be 2.

So the equation is: y = 4/3 x + 2

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What is the answer to A+5b=c for b? Im stuck

Nastasia [14]

I think you meant a+5(b)+c the answer is b is a unknown value

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3 years ago

Read 2 more answers

Which statement correctly describes this expression? 2m^3 -11

julsineya [31]

Answer:

Option A is the correct answer

Step-by-step explanation:

A. The difference of twice the cube of a number and 11

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2 years ago

Philip made a total of 9 bracelets and necklaces from 120 inches of cord. He used 8 inches of cord for each bracelet and 20 inch

Viktor [21]

Answer:

So Philip made 5 bracelets and 4 necklaces.

Step-by-step explanation:

Let x = number of bracelets and y = number of necklaces.

Since we have a total of 9 bracelets and necklaces,

x + y = 9 (1)

Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

So, the total length for both is 8x + 20y. Since the total length of cord used is 120 inches,

8x + 20y = 120 (2)

Simplifying it we have

2x + 5y = 30 (3).

Writing equations (1) and (3) in matrix form, we have

$\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]$

Using Cramer's rule to solve for x and y,

$x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

$y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

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3 years ago

Enn ran Four-fifths of a mile and then walked Seven-eighths of a mile around a track. Which expression can be used to find how m

Lapatulllka [165]

Answer:

ANSWER: A) 15/40 and 28/40

Step-by-step explanation: Ive done this before lol

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2 years ago

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RideAnS [48]

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