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Naily [24]
3 years ago
13

If a dies is rolled one time, find these probabilities. getting a number less than or equal to 4

Mathematics
1 answer:
trapecia [35]3 years ago
5 0
Hi there!

So let's see, we have a die and need to know the probability of rolling a number less than or equal to 4. Let's list the numbers that are less than or equal to 4: 1, 2, 3, 4. Now, since we know that there are 6 numbers on a die and 4 of them are less than or equal to 4, we can set up a fraction to find the percentage. The fraction would be 4/6 because 4 out of the 6 numbers on the die are less than or equal to 6. We can simplify 4/6 to 2/3 as well. To find the percentage, all we need to do is divide the numerator by the denominator. This leaves us with approximately 66.66%.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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Step-by-step explanation:

1. making the equation:

shoes = x

shirts = y

175 = x + 3y

x = 4y

2. graph it (I'm using desmos)

the green line is for 175 = x + 3y and the purple one is for x = 4y

3. find the price

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Suppose that, on average, electricians earn approximately μ= $54,000 per year in the united states. Assume that the distribution
11111nata11111 [884]

Answer:

0.15866.

Step-by-step explanation:

We have been given that on average, electricians earn approximately μ= $54,000 per year in the united states. Assume that the distribution for electricians' yearly earnings is normally distributed and that the standard deviation is σ= $12,000. We are asked to find the probability that the sample mean is greater than $66,000.

First of all, we will find the z-score corresponding to 66,000 using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{66000-54000}{12000}

z=\frac{12000}{12000}

z=1

Now, we need to find the probability that z-score is greater than 1 that is P(z>1).

Upon using formula P(z>A)=1-P(z, we will get:

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Upon using normal distribution table, we will get:

P(z>1)=1-0.84134

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