Answer:
Option C is right.
Step-by-step explanation:
Given is a graph with two triangles marked on it.
Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)
Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)
On comparison we find corresponding side of AB is A'B'
Length of AB = 8 and Length of A'B' = 4.
Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.
Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin. The degree of rotation is 180 degrees.
Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees
We have the slope m = (6-3)/(4-1) = 3/3 = 1;
Then, y - 3 = 1·( x - 1);
finally, y = x + 2.
Volume of a cube = (edge)^3
In this problem,
Volume = 216in^2
Edge = ?
Let's plug our values into the formula above.
216in^3 = (edge)^3
Take the cbrt of both sides.
6in = edge
The length of each edge = 6in
The first equation shows C and D, and the second shows C and B. The overlap will be at C, so thats the answer.
