we know that
If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation
we have the equation
Let's verify all the cases to determine the solution to the problem.
<u>case A)</u> point 
Substitute the values of x and y in the equation
-------> is true
therefore
The point is a solution of the equation
<u>case B)</u> point 
Substitute the values of x and y in the equation
-------> is true
therefore
The point is a solution of the equation
<u>case C)</u> point 
Substitute the values of x and y in the equation
-------> is not true
therefore
The point is not a solution of the equation
<u>case D)</u> point 
Substitute the values of x and y in the equation
-------> is not true
therefore
The point is not a solution of the equation
therefore
<u>the answer is </u>
Answer:
c is a multiple of 6
Step-by-step explanation:
Answer:
The answer to your question is: 16x + 3
Step-by-step explanation:
Step 1 : f(x) = 8x² + 3x
f(x +h) = 8(x + h)² + 3( x + h)
f(x + h) = 8( x² + 2xh + h²) + 3( x + h)
f (x + h) = 8x² + 16xh + 8h² + 3x + 3h
Step 2 f(x+h) - f(x) = 8x² + 16xh + 8h² + 3x + 3h - ( 8x² + 3x)
= 8x² + 16xh + 8h² + 3x + 3h - 8x² -3x
= 16xh + 8h² + 3 h
Step 3 f(x + h) - f(x)/ h = h(16x + 8h + 3) /h
= 16x + 8h + 3
Step 4 lim f(x + h) - f(x)/ h = lim 16x + 8h + 3 = lim 16x + 8(0) + 3 = 16x + 3
h ⇒0 h ⇒0 h ⇒0
Answer:
31
Step-by-step explanation:
16+14+1 = 31
There is a possibility that I pick out all (16) green marbles, then all (14) blue ones and the following (31-th) marble must be red
The solution to your problem is as follows:
The tangent line passes through (4,-6), so x = 4 when y = -6
=> f(4) = -6
The tangent line will have a constant gradient.
gradient is m = (-6 - 9)/(4 - 10) => 5/2
Equation is y - 9 = (5/2)(x - 10)
=> y - 9 = (5/2)(x-10)
<span>i.e. y = (5/2)(x-10) + 9
</span> y = (5/2)x - 25 + 9 = y = (5/2)x - 16
Now, f '(x) = dy/dx = 5/2
so, f '(4) = 5/2....i.e. gradient is 5/2 whatever the value of x.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
