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UkoKoshka [18]
3 years ago
15

Please help thank you :)​

Mathematics
2 answers:
Bad White [126]3 years ago
4 0

Answer:

ASA

Step-by-step explanation:

Hope it will help

plz brainlists

tamaranim1 [39]3 years ago
3 0

\:  \:  \:  \:  \:  \:  \red{ \underline{ \large{ \pink{ \tt{꧁ A \: N \: S \: W \: E \: R ꧂}}} }}

✧ \underline{ \underline{ \large{ \red{ \tt{G \: I\: V \: E\: N}}}} }:

  • AC bisects \tt{ \angle BAD\:  \& \:  \angle \: BCD}

❀ \underline{ \underline{ \large{ \tt{ \purple{T \: O \:  \: F \: I\: N\: D}}}}} :

  • Congruence theorem which justifies ∆ ABC \cong ∆ ADC.

♕ \underline{ \underline{ \large{ \tt{ \orange{P \: R\:O \: O \: F \: S}}} }}:

\begin{array}{ |c| c |  c |  } \hline \text{SN}& \text{Statement} &  \text{Reason}\\ \hline \\  \text{1 \: i.}& \sf{In \triangle} \:ABC \:    \& \:  \triangle \: ACD  \: \   \\ &  \tt{ \angle ACB=  \angle \: ACD(A)}\ &  \sf{AC \: bisects \angle \: BCD(Given)}   \\  \text{ii} \: &  \tt{AC= CA(S)}&  \sf{Common \: side} \\  \text{iii} \: &  \tt{ \angle \: BAC =  \angle \: CAD(A)}&  \sf{AC \: bisects \:  \angle \: BAD ( Given )}&  \\  \\ \hline 2& \tt{ \triangle} \: ABC  \cong  \triangle{ADC}&    \red{\underline{\sf{ \bold{By \: ASA\: axiom}}}} \\   \hline\end{array}

Hence , We can conclude :

  • ASA congruence theorem justifies ∆ ABC \cong ∆ ADC

ツ Hope I helped! ♡

♪ Have a wonderful day / night ! ✎

✎ \underbrace{ \overbrace{ \mathfrak{Carry \: On \:Learning}}} ☃

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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2 u + 12 &lt; 23<br> 0,1 d + 8 &gt; 0<br> 3 - 4 r &gt; 7<br> 13 &lt; 2 z + 3<br> 6 ≥ 9 - 0, 15 i
BartSMP [9]

Answer:

Part 1) u< 5.5  

Part 2) d > -80

Part 3) r < -1

Part 4) z>5

Part 5) i\geq 20

Step-by-step explanation:

<u><em>The question is</em></u>

Solve each inequality for the indicated variable

Part 1) we have

2u+12

subtract 12 both sides

2u< 23-12\\2u

Divide by 2 both sides

u< 5.5

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

0.1d+8 >0

subtract 8 both sides

0.1d > -8

Divide by 0.1 both sides

d > -80

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

3-4r> 7

Subtract 3 both sides

-4r>7-3\\-4r>4

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

r < -1

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

13< 2z+3

Subtract 3 both sides

13-3

Divide by 2 both sides

5

Rewrite

z>5

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

6\geq 9-0.15i

Subtract 9 both sides

6-9\geq -0.15i\\-3\geq -0.15i

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

20\leq i

Rewrite

i\geq 20

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0
3 years ago
Find the measure of the third angle of a triangle given the measures of two angles.<br> 34 and 88
romanna [79]

Answer:

58

Step-by-step explanation:

All three angles of a triangle have to add up to 180. Given this we can do the following problem:

180-34-88 = 58

3 0
3 years ago
Find the distance between each pair of points: (-2, -1) and (3, 11)​
Mumz [18]
Use the distance formula ! Hope this helped :)

6 0
2 years ago
2. Alicia is writing the program for a video game. For one part of the game she uses the rule to move points on the screen.
Gwar [14]

<em>Complete Question:</em>

<em>Alicia is writing the program for a video game. For one part of the game she uses the rule (x,y)->(x-3,y+4) to move points on the screen. </em>

<em>A) what output does the rule give when the input is (-6,0)? </em>

<em>B)What output does the rule give when the input is (3,-4)? </em>

<em>C) Is the rule a function? Explain why it is or why it is not </em>

Answer:

a. The output is (-9,4)

b. The output is (0,0)

c. See Explanation

Step-by-step explanation:

Given

Rule: (x,y)->(x - 3, y + 4)

Solving (a):

Inputs:

x = -6

y = 0

The outputs is as follows;

x => x - 3

x => -6 - 3

x => -9

y=> y + 4

y=> 0 + 4

y=> 4

Hence:

The output is (-9,4)

Solving (b):

Inputs:

x = 3

y = -4

The outputs is as follows;

x => x - 3

x=>3-3

x = 0

y=> y + 4

y=>-4+4

y=>0

Hence:

The output is (0,0)

Solving (c):

The function is a rule and the rule is that:

It shifts the graph left by 3 units and up by 4 units

5 0
2 years ago
I need help assap !!!!
tatiyna

Answer:

C & D

Step-by-step explanation:

Both have an odd amount of numbers, meaning there is a perfect middle.

8 0
3 years ago
Read 2 more answers
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