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3 years ago

Please help thank you :)

Mathematics

2 answers:

Bad White [126]3 years ago

4 0

Answer:

ASA

Step-by-step explanation:

Hope it will help

plz brainlists

tamaranim1 [39]3 years ago

3 0

$\: \: \: \: \: \: \red{ \underline{ \large{ \pink{ \tt{꧁ A \: N \: S \: W \: E \: R ꧂}}} }}$

✧ $\underline{ \underline{ \large{ \red{ \tt{G \: I\: V \: E\: N}}}} }:$

AC bisects $\tt{ \angle BAD\: \& \: \angle \: BCD}$

❀ $\underline{ \underline{ \large{ \tt{ \purple{T \: O \: \: F \: I\: N\: D}}}}} :$

Congruence theorem which justifies ∆ ABC $\cong$ ∆ ADC.

♕ $\underline{ \underline{ \large{ \tt{ \orange{P \: R\:O \: O \: F \: S}}} }}:$

$\begin{array}{ |c| c | c | } \hline \text{SN}& \text{Statement} & \text{Reason}\\ \hline \\ \text{1 \: i.}& \sf{In \triangle} \:ABC \: \& \: \triangle \: ACD \: \ \\ & \tt{ \angle ACB= \angle \: ACD(A)}\ & \sf{AC \: bisects \angle \: BCD(Given)} \\ \text{ii} \: & \tt{AC= CA(S)}& \sf{Common \: side} \\ \text{iii} \: & \tt{ \angle \: BAC = \angle \: CAD(A)}& \sf{AC \: bisects \: \angle \: BAD ( Given )}& \\ \\ \hline 2& \tt{ \triangle} \: ABC \cong \triangle{ADC}& \red{\underline{\sf{ \bold{By \: ASA\: axiom}}}} \\ \hline\end{array}$

Hence , We can conclude :

ASA congruence theorem justifies ∆ ABC $\cong$ ∆ ADC

ツ Hope I helped! ♡

♪ Have a wonderful day / night ! ✎

✎ $\underbrace{ \overbrace{ \mathfrak{Carry \: On \:Learning}}} ☃$

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I want you to imagine as you read this or you can draw through the help of my explanation and see yourself:

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That means in triangle ABD , one angle ADB is obtuse which means remaining <ABD and < BAD are acute. [PROVED]

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A standard oil drum is a cylinder with a volume of approximately 218.276 liters (or 0.218276 cubic meters). The cost of producin

Arte-miy333 [17]

Answer:

r = 2,85 feet

h = 8,56 feet

Step-by-step explanation:

Area of two circular caps (m ^(2)) : 2* pi* r^(2) (where r is the radius of circular cap) Area of wall (m ^(2)) is 2*pi*r*h (where h is the height of drum)

V= pi*r^(2)*h so h=V/pi*r^(2) (1)

Cost in $:

Cost of wall 25 $/m^(2) plus 10% for manufacturing so:

C(w) = 27,5*2*pi*r*h $/square feet

Cost of (both top and bottom cap) = 2*40,97*pi* r^(2) so:

C(caps) = 257,29* r^(2) $/squaer feet

Total cost of cylnder = cost of wall + cost of caps

Total cost f cylinder: F(c)= 55*pi*r*h+257,29* r^(2)

F(c) = 172,7*r*h + 257,29*r^(2) F(c) is F(r)

Since from (1) we have h=218,276/pi*r^(2)

F(r) = (172,7)*r*(69,514)/r^(2) +257,29*r^(2) F(c) = 12005/r + 257,29*r^(2)

Taken the first dervative

F´(r)= -12005*(1)/r^(2) +2*257,29*r F´(r) = -12005*(1)/r^(2) +514,58*r

f F´(r) = 0 -12005*(1)/r^(2) + 514,58*r =0

-120005 + 514,58*^(3) = 0 514,58*^(3) = 12005 r =cubic root (23,32)

r = 2,85 ft

if we replace this value en F(r) we can see F(r) tend to infinite both when r tend to 0 and when r tends to infnite so there is a minimun for the functon

r = 2,85 ft and h = 8,56 ft

5 0

3 years ago

Please help thank you :)​

Please help thank you :)