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3 years ago

Does a negative divided by a negative equal a positive

Mathematics

2 answers:

Lyrx [107]3 years ago

7 0

The answer is yes it dose

Kipish [7]3 years ago

3 0

A negative divided by a negative will result in a positive answer.

For example, (-16) ÷ (-2) = +8

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A picture is enlarged by keeping its width the same and increasing its length. The scatter plot shows the perimeter of the pictu

Brums [2.3K]

Answer: y = 2x + 20

Step-by-step explanation: slope, y2 - y1/x2 - x1

replace it with these numbers 120 - 60/50 - 20=60/30

than,simplified it we get 2/1. so, now we have the slope of our equation

y = 2x + b. but we still have b (or where the y intersects.) now are slope we have to change it to 1/2 because we are going backwards. So multiply 60 by .5, Thus will give us 30

Now we have y = 2x + 30, But that's not one of your answer,

So y = 2x + 20 cant be -20 because this is a positive y intersect and We know it is a slope of 2.

Therefore the answer is : y = 2x + 20

ALSO I got it correct on the test!!

3 0

3 years ago

The amount of time it takes a bat to eat a frog was recorded for each bat in a random sample of 12 bats. The resulting sample me

spin [16.1K]

Answer: a. CI for the mean: 17.327 < μ < 26.473

b. CI for variance: 29.7532 ≤ $\sigma^{2}$ ≤ 170.9093

Step-by-step explanation:

a. To construct a 95% confidence interval for the mean:

The given data are:

mean = 21.9

s = 7.7

n = 12

df = 12 - 1 = 11

1 - α = 0.05

$\frac{\alpha}{2}$ = 0.025

t-score = $t_{0.025,11}$ = 2.2001

Note: since the sample population is less than 30, it is used a t-score.

The formula for interval:

mean ± $t.\frac{s}{\sqrt{n} }$

Substituing values:

21.9 ± 2.200. $\frac{7.7}{\sqrt{12} }$

21.9 ± 4.573

The interval is: 17.327 < μ < 26.473

b. A 95% confidence interval for the variance:

The given values are:

$s^{2}$ = $7.7^{2}$

$s^{2}$ = 59.29

α = 0.05

$\frac{\alpha}{2}$ = 0.025

$1-\frac{\alpha}{2}$ = 0.975

$\chi^{2}_{0.025,11}$ = 21.92

$\chi^{2}_{0.975,11}$ = 3.816

Note: To find the values for $\chi^{2}_{\alpha/2,n-1}$ and $\chi^{2}_{1-\alpha/2,n-1}$ , look for them at the chi-square table

The formula to calculate interval:

( $\frac{(n-1).s^{2}}{\chi^{2}_{\alpha/2,n-1}} , \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2,n-1}}$ )

are the lower and upper limits, respectively.

Substituing values:

( $\frac{11.59.29}{21.92} , \frac{11.59.29}{3.816}$ )

(29.7532, 170.9093)

The interval for variance is: 29.7532 ≤ $\sigma^{2}$ ≤ 170.9093

6 0

3 years ago

5. x2 +5x-4 Discriminate

ikadub [295]

Answer:

D = 41

Step-by-step explanation:

y = ax² + bx + c

The discriminant D = b² - 4ac tells the types of roots the equation has.

If D < 0 , then quadratic equation has no real roots, has two imaginary roots.

If D = 0 , then quadratic equation has one real root.

If D > 0 , then quadratic equation has two distinct real roots.

~~~~~~~~~~~~

x² + 5x - 4

a = 1, b = 5, c = - 4

D = 5² - 4(1)(- 4) = 25 + 16 = 41

6 0

3 years ago

Find the slope of the line through each pair of points (-17, 11) , (-12, 9)

ad-work [718]

Answer:

M = -2/5

Step-by-step explanation:

To find the slope of a line when you know two points, use the following formula.

M = y₂ - y₁ ÷ x₂ - x₁

M = 9 - 11 ÷ -12 - (-17)

M = -2 ÷ 5

M = -2/5

Hope that helps.

3 0

3 years ago

Which equation is y = –3x2 – 12x – 2 rewritten in vertex form?

AlekseyPX

Answer:

The vertex form is y = -3(x + 2)² + 10

Step-by-step explanation:

* Lets revise how to put the quadratic in the vertex form

- The general form of the quadratic is y = ax² + bx + c, where

a , b , c are constants

# a is the coefficient of x²

# b is the coefficient of x

# c is the numerical term or the y-intercept

- The vertex form of the quadratic is a(x - h)² + k, where a, h , k

are constants

# a is the coefficient of x²

# h is the x-coordinate of the vertex point of the quadratic

# k is the y-coordinate of the vertex point of the quadratic

- We can find h from a and b ⇒ h = -b/a

- We find k by substitute the value of h instead of x in the general form

of the quadratic

k = ah² + bh + c

* Now lets solve the problem

∵ y = -3x² - 12x - 2

∵ y = ax² + bx + c

∴ a = -3 , b = -12

∵ h = -b/2a

∴ h = -(-12)/2(-3) = 12/-6 = -2

- Lets find k

∴ k = -3(-2)² - 12(-2) - 2 = -3(4) + 24 - 2 = -12 + 24 - 2 = 10

* Lets writ the vertex form

∵ y = a(x - h)² + k

∵ a = -3 , h = -2 , k = 10

∴ y = -3(x - -2)² + 10

∴ y = -3(x + 2)² + 10

* The vertex form is y = -3(x + 2)² + 10

6 0

3 years ago

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