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3 years ago

What is 58 times 8 using cumulative property

1 answer:

7 0

58 x 8 would be equal to 464. If you do 8 x 8 it'd be 64. And 8 x 50'd be 400. If you add up 64 + 400, you will get 464.

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g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

3 0

3 years ago

Find X <br> A. 50<br> B. 40<br> C.60<br> D.70

mart [117]

Answer:

b. 40

Step-by-step explanation:

The value of x (exterior angle) is equal to half of the difference of given arcs

(100 - 20) ÷ 2 = 40

4 0

3 years ago

Read 2 more answers

12.6 pounds equals how many ounces

Stells [14]

201.6 ounces
Hope this helps and please mark me as brainlest and like

4 0

3 years ago

What is the value of x in the equation x – y = 30, when y = 15?

joja [24]

I think isn't anyone of these alternatives because if we put number 15 in the place of y it is x-y=30. X-15=30
X=30+15=45.
X=45

4 0

2 years ago

The CEO of a large electric utility claims that more than 75 percent of his customers are very satisfied with the service they r

vichka [17]

Answer:

$z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462$

Now we can find the p value using the alternative hypothesis with this probability:

$p_v =P(z>0.462)=0.322$

Since the p value is large enough, we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

Step-by-step explanation:

Information provided

n=100 represent the random sample selected

$\hat p=0.77$ estimated proportion of students that are satisfied

is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if more than 75 percent of his customers are very satisfied with the service they receive, then the system of hypothesis is.:

Null hypothesis: $p\leq 0.75$

Alternative hypothesis: $p > 0.75$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462$

Now we can find the p value using the alternative hypothesis with this probability:

$p_v =P(z>0.462)=0.322$

Since the p value is large enough we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

4 0

3 years ago